Algebra Examples

|4x-12||4x12|
Step 1
To find the interval for the first piece, find where the inside of the absolute value is non-negative.
4x-1204x120
Step 2
Solve the inequality.
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Step 2.1
Add 1212 to both sides of the inequality.
4x124x12
Step 2.2
Divide each term in 4x124x12 by 44 and simplify.
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Step 2.2.1
Divide each term in 4x124x12 by 44.
4x41244x4124
Step 2.2.2
Simplify the left side.
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Step 2.2.2.1
Cancel the common factor of 44.
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Step 2.2.2.1.1
Cancel the common factor.
4x4124
Step 2.2.2.1.2
Divide x by 1.
x124
x124
x124
Step 2.2.3
Simplify the right side.
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Step 2.2.3.1
Divide 12 by 4.
x3
x3
x3
x3
Step 3
In the piece where 4x-12 is non-negative, remove the absolute value.
4x-12
Step 4
To find the interval for the second piece, find where the inside of the absolute value is negative.
4x-12<0
Step 5
Solve the inequality.
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Step 5.1
Add 12 to both sides of the inequality.
4x<12
Step 5.2
Divide each term in 4x<12 by 4 and simplify.
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Step 5.2.1
Divide each term in 4x<12 by 4.
4x4<124
Step 5.2.2
Simplify the left side.
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Step 5.2.2.1
Cancel the common factor of 4.
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Step 5.2.2.1.1
Cancel the common factor.
4x4<124
Step 5.2.2.1.2
Divide x by 1.
x<124
x<124
x<124
Step 5.2.3
Simplify the right side.
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Step 5.2.3.1
Divide 12 by 4.
x<3
x<3
x<3
x<3
Step 6
In the piece where 4x-12 is negative, remove the absolute value and multiply by -1.
-(4x-12)
Step 7
Write as a piecewise.
{4x-12x3-(4x-12)x<3
Step 8
Simplify -(4x-12).
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Step 8.1
Apply the distributive property.
{4x-12x3-(4x)--12x<3
Step 8.2
Multiply 4 by -1.
{4x-12x3-4x--12x<3
Step 8.3
Multiply -1 by -12.
{4x-12x3-4x+12x<3
{4x-12x3-4x+12x<3
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 [x2  12  π  xdx ] 
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