Examples
(5,18)(5,18) , (12,14)(12,14)
Step 1
To find the position vector, subtract the initial point vector PP from the terminal point vector QQ.
Q-P=(12i+14j)-(5i+18j)Q−P=(12i+14j)−(5i+18j)
Step 2
Step 2.1
Apply the distributive property.
12i+14j-(5i)-(18j)12i+14j−(5i)−(18j)
Step 2.2
Multiply 55 by -1−1.
12i+14j-5i-(18j)12i+14j−5i−(18j)
Step 2.3
Multiply 1818 by -1−1.
12i+14j-5i-18j12i+14j−5i−18j
12i+14j-5i-18j12i+14j−5i−18j
Step 3
Step 3.1
Subtract 5i5i from 12i12i.
14j+7i-18j14j+7i−18j
Step 3.2
Subtract 18j18j from 14j14j.
-4j+7i−4j+7i
-4j+7i−4j+7i
Step 4