Examples

[\begin{matrix} 2 & 4 - 2 & - 4 \end{matrix}] + [\begin{matrix} 4 & - 1 3 & 2 \end{matrix}]

$[\begin{array}{c} 2 & 4 \\ - 2 & - 4 \end{array}] + [\begin{array}{c} 4 & - 1 \\ 3 & 2 \end{array}]$

Step 1

Add the corresponding elements.

[\begin{matrix} 2 + 4 & 4 - 1 - 2 + 3 & - 4 + 2 \end{matrix}]

$[\begin{array}{c} 2 + 4 & 4 - 1 \\ - 2 + 3 & - 4 + 2 \end{array}]$

Step 2

Simplify each element.

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Step 2.1

Add

2

$2$ and

4

$4$ .

[\begin{matrix} 6 & 4 - 1 - 2 + 3 & - 4 + 2 \end{matrix}]

$[\begin{array}{c} 6 & 4 - 1 \\ - 2 + 3 & - 4 + 2 \end{array}]$

Step 2.2

Subtract

1

$1$ from

4

$4$ .

[\begin{matrix} 6 & 3 - 2 + 3 & - 4 + 2 \end{matrix}]

$[\begin{array}{c} 6 & 3 \\ - 2 + 3 & - 4 + 2 \end{array}]$

Step 2.3

Add

- 2

$- 2$ and

3

$3$ .

[\begin{matrix} 6 & 3 1 & - 4 + 2 \end{matrix}]

$[\begin{array}{c} 6 & 3 \\ 1 & - 4 + 2 \end{array}]$

Step 2.4

Add

- 4

$- 4$ and

2

$2$ .

[\begin{matrix} 6 & 3 1 & - 2 \end{matrix}]

$[\begin{array}{c} 6 & 3 \\ 1 & - 2 \end{array}]$

[\begin{matrix} 6 & 3 1 & - 2 \end{matrix}]

$[\begin{array}{c} 6 & 3 \\ 1 & - 2 \end{array}]$

Step 3

The determinant of a

2 \times 2

$2 \times 2$ matrix can be found using the formula

∣ ∣ ∣ \begin{matrix} a & b c & d \end{matrix} ∣ ∣ ∣ = a d - c b

$| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ .

6 \cdot - 2 - 1 \cdot 3

$6 \cdot - 2 - 1 \cdot 3$

Step 4

Simplify the determinant.

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Step 4.1

Simplify each term.

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Step 4.1.1

Multiply

6

$6$ by

- 2

$- 2$ .

- 12 - 1 \cdot 3

$- 12 - 1 \cdot 3$

Step 4.1.2

Multiply

- 1

$- 1$ by

3

$3$ .

- 12 - 3

$- 12 - 3$

- 12 - 3

$- 12 - 3$

Step 4.2

Subtract

3

$3$ from

- 12

$- 12$ .

- 15

$- 15$

- 15

$- 15$

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