Examples

Find the Expanded Form
2(x-1)2-(3y-4)2=252(x1)2(3y4)2=25
Step 1
Simplify the left side 2(x-1)2-(3y-4)22(x1)2(3y4)2.
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Step 1.1
Simplify each term.
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Step 1.1.1
Rewrite (x-1)2(x1)2 as (x-1)(x-1)(x1)(x1).
2((x-1)(x-1))-(3y-4)2=252((x1)(x1))(3y4)2=25
Step 1.1.2
Expand (x-1)(x-1)(x1)(x1) using the FOIL Method.
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Step 1.1.2.1
Apply the distributive property.
2(x(x-1)-1(x-1))-(3y-4)2=252(x(x1)1(x1))(3y4)2=25
Step 1.1.2.2
Apply the distributive property.
2(xx+x-1-1(x-1))-(3y-4)2=252(xx+x11(x1))(3y4)2=25
Step 1.1.2.3
Apply the distributive property.
2(xx+x-1-1x-1-1)-(3y-4)2=252(xx+x11x11)(3y4)2=25
2(xx+x-1-1x-1-1)-(3y-4)2=252(xx+x11x11)(3y4)2=25
Step 1.1.3
Simplify and combine like terms.
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Step 1.1.3.1
Simplify each term.
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Step 1.1.3.1.1
Multiply xx by xx.
2(x2+x-1-1x-1-1)-(3y-4)2=252(x2+x11x11)(3y4)2=25
Step 1.1.3.1.2
Move -11 to the left of xx.
2(x2-1x-1x-1-1)-(3y-4)2=252(x21x1x11)(3y4)2=25
Step 1.1.3.1.3
Rewrite -1x1x as -xx.
2(x2-x-1x-1-1)-(3y-4)2=252(x2x1x11)(3y4)2=25
Step 1.1.3.1.4
Rewrite -1x1x as -xx.
2(x2-x-x-1-1)-(3y-4)2=252(x2xx11)(3y4)2=25
Step 1.1.3.1.5
Multiply -11 by -11.
2(x2-x-x+1)-(3y-4)2=252(x2xx+1)(3y4)2=25
2(x2-x-x+1)-(3y-4)2=252(x2xx+1)(3y4)2=25
Step 1.1.3.2
Subtract xx from -xx.
2(x2-2x+1)-(3y-4)2=252(x22x+1)(3y4)2=25
2(x2-2x+1)-(3y-4)2=252(x22x+1)(3y4)2=25
Step 1.1.4
Apply the distributive property.
2x2+2(-2x)+21-(3y-4)2=252x2+2(2x)+21(3y4)2=25
Step 1.1.5
Simplify.
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Step 1.1.5.1
Multiply -22 by 22.
2x2-4x+21-(3y-4)2=252x24x+21(3y4)2=25
Step 1.1.5.2
Multiply 22 by 11.
2x2-4x+2-(3y-4)2=252x24x+2(3y4)2=25
2x2-4x+2-(3y-4)2=252x24x+2(3y4)2=25
Step 1.1.6
Rewrite (3y-4)2(3y4)2 as (3y-4)(3y-4)(3y4)(3y4).
2x2-4x+2-((3y-4)(3y-4))=252x24x+2((3y4)(3y4))=25
Step 1.1.7
Expand (3y-4)(3y-4)(3y4)(3y4) using the FOIL Method.
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Step 1.1.7.1
Apply the distributive property.
2x2-4x+2-(3y(3y-4)-4(3y-4))=252x24x+2(3y(3y4)4(3y4))=25
Step 1.1.7.2
Apply the distributive property.
2x2-4x+2-(3y(3y)+3y-4-4(3y-4))=252x24x+2(3y(3y)+3y44(3y4))=25
Step 1.1.7.3
Apply the distributive property.
2x2-4x+2-(3y(3y)+3y-4-4(3y)-4-4)=252x24x+2(3y(3y)+3y44(3y)44)=25
2x2-4x+2-(3y(3y)+3y-4-4(3y)-4-4)=252x24x+2(3y(3y)+3y44(3y)44)=25
Step 1.1.8
Simplify and combine like terms.
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Step 1.1.8.1
Simplify each term.
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Step 1.1.8.1.1
Rewrite using the commutative property of multiplication.
2x2-4x+2-(3(3yy)+3y-4-4(3y)-4-4)=252x24x+2(3(3yy)+3y44(3y)44)=25
Step 1.1.8.1.2
Multiply yy by yy by adding the exponents.
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Step 1.1.8.1.2.1
Move yy.
2x2-4x+2-(3(3(yy))+3y-4-4(3y)-4-4)=252x24x+2(3(3(yy))+3y44(3y)44)=25
Step 1.1.8.1.2.2
Multiply yy by yy.
2x2-4x+2-(3(3y2)+3y-4-4(3y)-4-4)=252x24x+2(3(3y2)+3y44(3y)44)=25
2x2-4x+2-(3(3y2)+3y-4-4(3y)-4-4)=252x24x+2(3(3y2)+3y44(3y)44)=25
Step 1.1.8.1.3
Multiply 33 by 33.
2x2-4x+2-(9y2+3y-4-4(3y)-4-4)=252x24x+2(9y2+3y44(3y)44)=25
Step 1.1.8.1.4
Multiply -44 by 33.
2x2-4x+2-(9y2-12y-4(3y)-4-4)=252x24x+2(9y212y4(3y)44)=25
Step 1.1.8.1.5
Multiply 33 by -44.
2x2-4x+2-(9y2-12y-12y-4-4)=252x24x+2(9y212y12y44)=25
Step 1.1.8.1.6
Multiply -44 by -44.
2x2-4x+2-(9y2-12y-12y+16)=252x24x+2(9y212y12y+16)=25
2x2-4x+2-(9y2-12y-12y+16)=252x24x+2(9y212y12y+16)=25
Step 1.1.8.2
Subtract 12y12y from -12y12y.
2x2-4x+2-(9y2-24y+16)=252x24x+2(9y224y+16)=25
2x2-4x+2-(9y2-24y+16)=25
Step 1.1.9
Apply the distributive property.
2x2-4x+2-(9y2)-(-24y)-116=25
Step 1.1.10
Simplify.
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Step 1.1.10.1
Multiply 9 by -1.
2x2-4x+2-9y2-(-24y)-116=25
Step 1.1.10.2
Multiply -24 by -1.
2x2-4x+2-9y2+24y-116=25
Step 1.1.10.3
Multiply -1 by 16.
2x2-4x+2-9y2+24y-16=25
2x2-4x+2-9y2+24y-16=25
2x2-4x+2-9y2+24y-16=25
Step 1.2
Simplify the expression.
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Step 1.2.1
Subtract 16 from 2.
2x2-4x-9y2+24y-14=25
Step 1.2.2
Move -4x.
2x2-9y2-4x+24y-14=25
2x2-9y2-4x+24y-14=25
2x2-9y2-4x+24y-14=25
Step 2
Set the equation equal to zero.
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Step 2.1
Subtract 25 from both sides of the equation.
2x2-9y2-4x+24y-14-25=0
Step 2.2
Subtract 25 from -14.
2x2-9y2-4x+24y-39=0
2x2-9y2-4x+24y-39=0
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