Matemática discreta Ejemplos

$[\begin{array}{c} 15 & 8 \\ 4 x & 0 \end{array}] - [\begin{array}{c} 2 & 5 \\ x & 3 y + 6 \end{array}] = [\begin{array}{c} 13 & 3 \\ 12 & 4 y + 8 \end{array}]$

Paso 1

Resta los elementos correspondientes.

$[\begin{array}{c} 15 - 2 & 8 - 5 \\ 4 x - x & 0 - (3 y + 6) \end{array}] = [\begin{array}{c} 13 & 3 \\ 12 & 4 y + 8 \end{array}]$

Paso 2

Simplify each element.

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Paso 2.1

Resta $2$ de $15$ .

$[\begin{array}{c} 13 & 8 - 5 \\ 4 x - x & 0 - (3 y + 6) \end{array}] = [\begin{array}{c} 13 & 3 \\ 12 & 4 y + 8 \end{array}]$

Paso 2.2

Resta $5$ de $8$ .

$[\begin{array}{c} 13 & 3 \\ 4 x - x & 0 - (3 y + 6) \end{array}] = [\begin{array}{c} 13 & 3 \\ 12 & 4 y + 8 \end{array}]$

Paso 2.3

Resta $x$ de $4 x$ .

$[\begin{array}{c} 13 & 3 \\ 3 x & 0 - (3 y + 6) \end{array}] = [\begin{array}{c} 13 & 3 \\ 12 & 4 y + 8 \end{array}]$

Paso 2.4

Resta $3 y + 6$ de $0$ .

$[\begin{array}{c} 13 & 3 \\ 3 x & - (3 y + 6) \end{array}] = [\begin{array}{c} 13 & 3 \\ 12 & 4 y + 8 \end{array}]$

Paso 2.5

Aplica la propiedad distributiva.

$[\begin{array}{c} 13 & 3 \\ 3 x & - (3 y) - 1 \cdot 6 \end{array}] = [\begin{array}{c} 13 & 3 \\ 12 & 4 y + 8 \end{array}]$

Paso 2.6

Multiplica $3$ por $- 1$ .

$[\begin{array}{c} 13 & 3 \\ 3 x & - 3 y - 1 \cdot 6 \end{array}] = [\begin{array}{c} 13 & 3 \\ 12 & 4 y + 8 \end{array}]$

Paso 2.7

Multiplica $- 1$ por $6$ .

$[\begin{array}{c} 13 & 3 \\ 3 x & - 3 y - 6 \end{array}] = [\begin{array}{c} 13 & 3 \\ 12 & 4 y + 8 \end{array}]$

Paso 3

Write as a linear system of equations.

$13 = 13$

$3 = 3$

$3 x = 12$

$- 3 y - 6 = 4 y + 8$

Paso 4

Since $3 = 3$ is always true, the matrix equation has infinite solutions.

Infinite solutions satisfying the system.