Matemática discreta Ejemplos

$3 x \cdot 1 + 7 x \cdot 2 - x \cdot 3 = 11$ , $x \cdot 1 + 2 x \cdot 2 - x \cdot 3 = 3$ , $2 x \cdot 1 + 4 x \cdot 2 - 2 x \cdot 3 = 10$

Paso 1

Move variables to the left and constant terms to the right.

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Paso 1.1

Combina los términos opuestos en $3 x \cdot 1 + 7 x \cdot 2 - x \cdot 3$ .

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Paso 1.1.1

Reordena los factores en los términos $3 x \cdot 1$ y $- x \cdot 3$ .

$1 \cdot 3 x + 7 x \cdot 2 - 1 \cdot 3 x = 11$

$x \cdot 1 + 2 x \cdot 2 - x \cdot 3 = 3$

$2 x \cdot 1 + 4 x \cdot 2 - 2 x \cdot 3 = 10$

Paso 1.1.2

Resta $3 x$ de $1 \cdot 3 x$ .

$7 x \cdot 2 + 0 = 11$

$x \cdot 1 + 2 x \cdot 2 - x \cdot 3 = 3$

$2 x \cdot 1 + 4 x \cdot 2 - 2 x \cdot 3 = 10$

Paso 1.1.3

Suma $7 x \cdot 2$ y $0$ .

$7 x \cdot 2 = 11$

$x \cdot 1 + 2 x \cdot 2 - x \cdot 3 = 3$

$2 x \cdot 1 + 4 x \cdot 2 - 2 x \cdot 3 = 10$

$7 x \cdot 2 = 11$

$x \cdot 1 + 2 x \cdot 2 - x \cdot 3 = 3$

$2 x \cdot 1 + 4 x \cdot 2 - 2 x \cdot 3 = 10$

Paso 1.2

Multiplica $2$ por $7$ .

$14 x = 11$

$x \cdot 1 + 2 x \cdot 2 - x \cdot 3 = 3$

$2 x \cdot 1 + 4 x \cdot 2 - 2 x \cdot 3 = 10$

Paso 1.3

Simplifica cada término.

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Paso 1.3.1

Multiplica $x$ por $1$ .

$14 x = 11$

$x + 2 x \cdot 2 - x \cdot 3 = 3$

$2 x \cdot 1 + 4 x \cdot 2 - 2 x \cdot 3 = 10$

Paso 1.3.2

Multiplica $2$ por $2$ .

$14 x = 11$

$x + 4 x - x \cdot 3 = 3$

$2 x \cdot 1 + 4 x \cdot 2 - 2 x \cdot 3 = 10$

Paso 1.3.3

Multiplica $3$ por $- 1$ .

$14 x = 11$

$x + 4 x - 3 x = 3$

$2 x \cdot 1 + 4 x \cdot 2 - 2 x \cdot 3 = 10$

$14 x = 11$

$x + 4 x - 3 x = 3$

$2 x \cdot 1 + 4 x \cdot 2 - 2 x \cdot 3 = 10$

Paso 1.4

Suma $x$ y $4 x$ .

$14 x = 11$

$5 x - 3 x = 3$

$2 x \cdot 1 + 4 x \cdot 2 - 2 x \cdot 3 = 10$

Paso 1.5

Resta $3 x$ de $5 x$ .

$14 x = 11$

$2 x = 3$

$2 x \cdot 1 + 4 x \cdot 2 - 2 x \cdot 3 = 10$

Paso 1.6

Simplifica cada término.

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Paso 1.6.1

Multiplica $2$ por $1$ .

$14 x = 11$

$2 x = 3$

$2 x + 4 x \cdot 2 - 2 x \cdot 3 = 10$

Paso 1.6.2

Multiplica $2$ por $4$ .

$14 x = 11$

$2 x = 3$

$2 x + 8 x - 2 x \cdot 3 = 10$

Paso 1.6.3

Multiplica $3$ por $- 2$ .

$14 x = 11$

$2 x = 3$

$2 x + 8 x - 6 x = 10$

$14 x = 11$

$2 x = 3$

$2 x + 8 x - 6 x = 10$

Paso 1.7

Suma $2 x$ y $8 x$ .

$14 x = 11$

$2 x = 3$

$10 x - 6 x = 10$

Paso 1.8

Resta $6 x$ de $10 x$ .

$14 x = 11$

$2 x = 3$

$4 x = 10$

$14 x = 11$

$2 x = 3$

$4 x = 10$

Paso 2

Write the system as a matrix.

$[\begin{array}{c} 14 & 11 \\ 2 & 3 \\ 4 & 10 \end{array}]$

Paso 3

Obtén la forma escalonada reducida por filas.

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Paso 3.1

Multiply each element of $R_{1}$ by $\frac{1}{14}$ to make the entry at $1, 1$ a $1$ .

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Paso 3.1.1

Multiply each element of $R_{1}$ by $\frac{1}{14}$ to make the entry at $1, 1$ a $1$ .

$[\begin{array}{c} \frac{14}{14} & \frac{11}{14} \\ 2 & 3 \\ 4 & 10 \end{array}]$

Paso 3.1.2

Simplifica $R_{1}$ .

$[\begin{array}{c} 1 & \frac{11}{14} \\ 2 & 3 \\ 4 & 10 \end{array}]$

Paso 3.2

Perform the row operation $R_{2} = R_{2} - 2 R_{1}$ to make the entry at $2, 1$ a $0$ .

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Paso 3.2.1

Perform the row operation $R_{2} = R_{2} - 2 R_{1}$ to make the entry at $2, 1$ a $0$ .

$[\begin{array}{c} 1 & \frac{11}{14} \\ 2 - 2 \cdot 1 & 3 - 2 (\frac{11}{14}) \\ 4 & 10 \end{array}]$

Paso 3.2.2

Simplifica $R_{2}$ .

$[\begin{array}{c} 1 & \frac{11}{14} \\ 0 & \frac{10}{7} \\ 4 & 10 \end{array}]$

Paso 3.3

Perform the row operation $R_{3} = R_{3} - 4 R_{1}$ to make the entry at $3, 1$ a $0$ .

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Paso 3.3.1

Perform the row operation $R_{3} = R_{3} - 4 R_{1}$ to make the entry at $3, 1$ a $0$ .

$[\begin{array}{c} 1 & \frac{11}{14} \\ 0 & \frac{10}{7} \\ 4 - 4 \cdot 1 & 10 - 4 (\frac{11}{14}) \end{array}]$

Paso 3.3.2

Simplifica $R_{3}$ .

$[\begin{array}{c} 1 & \frac{11}{14} \\ 0 & \frac{10}{7} \\ 0 & \frac{48}{7} \end{array}]$

Paso 3.4

Multiply each element of $R_{2}$ by $\frac{7}{10}$ to make the entry at $2, 2$ a $1$ .

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Paso 3.4.1

Multiply each element of $R_{2}$ by $\frac{7}{10}$ to make the entry at $2, 2$ a $1$ .

$[\begin{array}{c} 1 & \frac{11}{14} \\ \frac{7}{10} \cdot 0 & \frac{7}{10} \cdot \frac{10}{7} \\ 0 & \frac{48}{7} \end{array}]$

Paso 3.4.2

Simplifica $R_{2}$ .

$[\begin{array}{c} 1 & \frac{11}{14} \\ 0 & 1 \\ 0 & \frac{48}{7} \end{array}]$

Paso 3.5

Perform the row operation $R_{3} = R_{3} - \frac{48}{7} R_{2}$ to make the entry at $3, 2$ a $0$ .

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Paso 3.5.1

Perform the row operation $R_{3} = R_{3} - \frac{48}{7} R_{2}$ to make the entry at $3, 2$ a $0$ .

$[\begin{array}{c} 1 & \frac{11}{14} \\ 0 & 1 \\ 0 - \frac{48}{7} \cdot 0 & \frac{48}{7} - \frac{48}{7} \cdot 1 \end{array}]$

Paso 3.5.2

Simplifica $R_{3}$ .

$[\begin{array}{c} 1 & \frac{11}{14} \\ 0 & 1 \\ 0 & 0 \end{array}]$

Paso 3.6

Perform the row operation $R_{1} = R_{1} - \frac{11}{14} R_{2}$ to make the entry at $1, 2$ a $0$ .

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Paso 3.6.1

Perform the row operation $R_{1} = R_{1} - \frac{11}{14} R_{2}$ to make the entry at $1, 2$ a $0$ .

$[\begin{array}{c} 1 - \frac{11}{14} \cdot 0 & \frac{11}{14} - \frac{11}{14} \cdot 1 \\ 0 & 1 \\ 0 & 0 \end{array}]$

Paso 3.6.2

Simplifica $R_{1}$ .

$[\begin{array}{c} 1 & 0 \\ 0 & 1 \\ 0 & 0 \end{array}]$

Paso 4

Use the result matrix to declare the final solution to the system of equations.

$x = 0$

$0 = 1$

$0 = 0$

Paso 5

The solution is the set of ordered pairs that make the system true.

$(error = error)$