Matemática discreta Ejemplos

$c = 15 x + 600$ , $r = 30 x$

Paso 1

Move variables to the left and constant terms to the right.

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Paso 1.1

Resta $15 x$ de ambos lados de la ecuación.

$c - 15 x = 600$

$r = 30 x$

Paso 1.2

Resta $30 x$ de ambos lados de la ecuación.

$c - 15 x = 600$

$r - 30 x = 0$

$c - 15 x = 600$

$r - 30 x = 0$

Paso 2

Write the system as a matrix.

$[\begin{array}{c} 1 & 0 & - 15 & 600 \\ 0 & 1 & - 30 & 0 \end{array}]$

Paso 3

Use the result matrix to declare the final solution to the system of equations.

$c - 15 x = 600$

$r - 30 x = 0$

Paso 4

The solution is the set of ordered pairs that make the system true.

$(600 + 15 x, 30 x, x)$