Química Ejemplos

$T cN e T e R e R b E u B kA m P m$

Paso 1

Para obtener la masa de $1$ mol de $T cN e T e R e R b E u B kA m P m$ , obtén la masa atómica de cada elemento y multiplícala por la cantidad de átomos contenidos en cada elemento en la molécula.

mass of $1$ mole of $T cN e T e R e R b E u B kA m P m$ $=$ $(mass of T)$ + $(mass of U)$ + $(mass of N)$ + $(mass of I)$ + $(mass of T>c)$ + $(mass of N)$ + $(mass of Te)$ + $(mass of Re)$ + $(mass of Rb)$ + $(mass of Eu)$ + $(mass of B)$ + $(mass of U)$ + $(mass of N)$ + $(mass of I)$ + $(mass of T>k)$ + $(mass of A)$ + $(mass of Pm)$

Paso 2

Completa con las masas atómicas de la tabla periódica.

mass of $1$ mole of $T cN e T e R e R b E u B kA m P m$ $=$ $(0)$ + $(238.02999877)$ + $(14.01000022)$ + $(126.90000152)$ + $(0)$ + $(14.01000022)$ + $(127.59999847)$ + $(186.21000671)$ + $(85.48000335)$ + $(151.96000671)$ + $(10.81000041)$ + $(238.02999877)$ + $(14.01000022)$ + $(126.90000152)$ + $(0)$ + $(0)$ + $(145)$

Paso 3

Simplifica el resultado.

Toca para ver más pasos...

Paso 3.1

Elimina los paréntesis.

masa de $1$ mol de $T cN e T e R e R b E u B kA m P m = 0 + 238.02999877 + 14.01000022 + 126.90000152 + 0 + 14.01000022 + 127.59999847 + 186.21000671 + 85.48000335 + 151.96000671 + 10.81000041 + 238.02999877 + 14.01000022 + 126.90000152 + 0 + 0 + 145 g$

Paso 3.2

Suma $0$ y $238.02999877$ .

masa de $1$ mol de $T cN e T e R e R b E u B kA m P m = 238.02999877 + 14.01000022 + 126.90000152 + 0 + 14.01000022 + 127.59999847 + 186.21000671 + 85.48000335 + 151.96000671 + 10.81000041 + 238.02999877 + 14.01000022 + 126.90000152 + 0 + 0 + 145 g$

Paso 3.3

Suma $238.02999877$ y $14.01000022$ .

masa de $1$ mol de $T cN e T e R e R b E u B kA m P m = 252.039999 + 126.90000152 + 0 + 14.01000022 + 127.59999847 + 186.21000671 + 85.48000335 + 151.96000671 + 10.81000041 + 238.02999877 + 14.01000022 + 126.90000152 + 0 + 0 + 145 g$

Paso 3.4

Suma $252.039999$ y $126.90000152$ .

masa de $1$ mol de $T cN e T e R e R b E u B kA m P m = 378.94000053 + 0 + 14.01000022 + 127.59999847 + 186.21000671 + 85.48000335 + 151.96000671 + 10.81000041 + 238.02999877 + 14.01000022 + 126.90000152 + 0 + 0 + 145 g$

Paso 3.5

Suma $378.94000053$ y $0$ .

masa de $1$ mol de $T cN e T e R e R b E u B kA m P m = 378.94000053 + 14.01000022 + 127.59999847 + 186.21000671 + 85.48000335 + 151.96000671 + 10.81000041 + 238.02999877 + 14.01000022 + 126.90000152 + 0 + 0 + 145 g$

Paso 3.6

Suma $378.94000053$ y $14.01000022$ .

masa de $1$ mol de $T cN e T e R e R b E u B kA m P m = 392.95000076 + 127.59999847 + 186.21000671 + 85.48000335 + 151.96000671 + 10.81000041 + 238.02999877 + 14.01000022 + 126.90000152 + 0 + 0 + 145 g$

Paso 3.7

Suma $392.95000076$ y $127.59999847$ .

masa de $1$ mol de $T cN e T e R e R b E u B kA m P m = 520.54999923 + 186.21000671 + 85.48000335 + 151.96000671 + 10.81000041 + 238.02999877 + 14.01000022 + 126.90000152 + 0 + 0 + 145 g$

Paso 3.8

Suma $520.54999923$ y $186.21000671$ .

masa de $1$ mol de $T cN e T e R e R b E u B kA m P m = 706.76000595 + 85.48000335 + 151.96000671 + 10.81000041 + 238.02999877 + 14.01000022 + 126.90000152 + 0 + 0 + 145 g$

Paso 3.9

Suma $706.76000595$ y $85.48000335$ .

masa de $1$ mol de $T cN e T e R e R b E u B kA m P m = 792.2400093 + 151.96000671 + 10.81000041 + 238.02999877 + 14.01000022 + 126.90000152 + 0 + 0 + 145 g$

Paso 3.10

Suma $792.2400093$ y $151.96000671$ .

masa de $1$ mol de $T cN e T e R e R b E u B kA m P m = 944.20001602 + 10.81000041 + 238.02999877 + 14.01000022 + 126.90000152 + 0 + 0 + 145 g$

Paso 3.11

Suma $944.20001602$ y $10.81000041$ .

masa de $1$ mol de $T cN e T e R e R b E u B kA m P m = 955.01001644 + 238.02999877 + 14.01000022 + 126.90000152 + 0 + 0 + 145 g$

Paso 3.12

Suma $955.01001644$ y $238.02999877$ .

masa de $1$ mol de $T cN e T e R e R b E u B kA m P m = 1193.04001522 + 14.01000022 + 126.90000152 + 0 + 0 + 145 g$

Paso 3.13

Suma $1193.04001522$ y $14.01000022$ .

masa de $1$ mol de $T cN e T e R e R b E u B kA m P m = 1207.05001544 + 126.90000152 + 0 + 0 + 145 g$

Paso 3.14

Suma $1207.05001544$ y $126.90000152$ .

masa de $1$ mol de $T cN e T e R e R b E u B kA m P m = 1333.95001697 + 0 + 0 + 145 g$

Paso 3.15

Suma $1333.95001697$ y $0$ .

masa de $1$ mol de $T cN e T e R e R b E u B kA m P m = 1333.95001697 + 0 + 145 g$

Paso 3.16

Suma $1333.95001697$ y $0$ .

masa de $1$ mol de $T cN e T e R e R b E u B kA m P m = 1333.95001697 + 145 g$

Paso 3.17

Suma $1333.95001697$ y $145$ .

masa de $1$ mol de $T cN e T e R e R b E u B kA m P m = 1478.95001697 g$