Ejemplos
(7,2,9)(7,2,9) , (10,1,1)(10,1,1)
Paso 1
To find the distance between two 3d points, square the difference of the x, y, and z points. Then, sum them and take the square root.
√(x2-x1)2+(y2-y1)2+(z2-z1)2√(x2−x1)2+(y2−y1)2+(z2−z1)2
Paso 2
Reemplaza x1x1, x2x2, y1y1, y2y2, z1z1 y z2z2 con los valores correspondientes.
Distance=√(10-7)2+(1-2)2+(1-9)2Distance=√(10−7)2+(1−2)2+(1−9)2
Paso 3
Paso 3.1
Resta 77 de 1010.
Distance=√32+(1-2)2+(1-9)2Distance=√32+(1−2)2+(1−9)2
Paso 3.2
Eleva 33 a la potencia de 22.
Distance=√9+(1-2)2+(1-9)2Distance=√9+(1−2)2+(1−9)2
Paso 3.3
Resta 22 de 11.
Distance=√9+(-1)2+(1-9)2Distance=√9+(−1)2+(1−9)2
Paso 3.4
Eleva -1−1 a la potencia de 22.
Distance=√9+1+(1-9)2Distance=√9+1+(1−9)2
Paso 3.5
Resta 99 de 11.
Distance=√9+1+(-8)2Distance=√9+1+(−8)2
Paso 3.6
Eleva -8−8 a la potencia de 22.
Distance=√9+1+64Distance=√9+1+64
Paso 3.7
Suma 99 y 11.
Distance=√10+64Distance=√10+64
Paso 3.8
Suma 1010 y 6464.
Distance=√74Distance=√74
Distance=√74Distance=√74
Paso 4
La distancia entre (7,2,9)(7,2,9) y (10,1,1)(10,1,1) es √74√74.
√74≈8.60232526√74≈8.60232526