Elementarmathematik Beispiele

$f (x) = 7 (x^{\frac{1}{5}} + 7)$ ; find $f^{- 1} (x)$

Schritt 1

Schreibe $f (x) = 7 (x^{\frac{1}{5}} + 7)$ als Gleichung.

$y = 7 (x^{\frac{1}{5}} + 7)$

Schritt 2

Vertausche die Variablen.

$x = 7 (y^{\frac{1}{5}} + 7)$

Schritt 3

Löse nach $y$ auf.

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Schritt 3.1

Schreibe die Gleichung als $7 (y^{\frac{1}{5}} + 7) = x$ um.

$7 (y^{\frac{1}{5}} + 7) = x$

Schritt 3.2

Teile jeden Ausdruck in $7 (y^{\frac{1}{5}} + 7) = x$ durch $7$ und vereinfache.

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Schritt 3.2.1

Teile jeden Ausdruck in $7 (y^{\frac{1}{5}} + 7) = x$ durch $7$ .

$\frac{7 (y^{\frac{1}{5}} + 7)}{7} = \frac{x}{7}$

Schritt 3.2.2

Vereinfache die linke Seite.

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Schritt 3.2.2.1

Kürze den gemeinsamen Faktor.

$\frac{7 (y^{\frac{1}{5}} + 7)}{7} = \frac{x}{7}$

Schritt 3.2.2.2

Dividiere $y^{\frac{1}{5}} + 7$ durch $1$ .

$y^{\frac{1}{5}} + 7 = \frac{x}{7}$

Schritt 3.3

Bringe alle Terme, die nicht $y$ enthalten, auf die rechte Seite der Gleichung.

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Schritt 3.3.1

Subtrahiere $7$ von beiden Seiten der Gleichung.

$y^{\frac{1}{5}} - \frac{x}{7} = - 7$

Schritt 3.3.2

Addiere $\frac{x}{7}$ zu beiden Seiten der Gleichung.

$y^{\frac{1}{5}} = - 7 + \frac{x}{7}$

Schritt 3.4

Potenziere jede Seite der Gleichung mit $5$ , um den gebrochenen Exponenten auf der linken Seite zu eliminieren.

${(y^{\frac{1}{5}})}^{5} = {(- 7 + \frac{x}{7})}^{5}$

Schritt 3.5

Vereinfache den Exponenten.

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Schritt 3.5.1

Vereinfache die linke Seite.

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Schritt 3.5.1.1

Vereinfache ${(y^{\frac{1}{5}})}^{5}$ .

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Schritt 3.5.1.1.1

Multipliziere die Exponenten in ${(y^{\frac{1}{5}})}^{5}$ .

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Schritt 3.5.1.1.1.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$y^{\frac{1}{5} \cdot 5} = {(- 7 + \frac{x}{7})}^{5}$

Schritt 3.5.1.1.1.2

Kürze den gemeinsamen Faktor von $5$ .

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Schritt 3.5.1.1.1.2.1

Kürze den gemeinsamen Faktor.

$y^{\frac{1}{5} \cdot 5} = {(- 7 + \frac{x}{7})}^{5}$

Schritt 3.5.1.1.1.2.2

Forme den Ausdruck um.

$y^{1} = {(- 7 + \frac{x}{7})}^{5}$

Schritt 3.5.1.1.2

Vereinfache.

$y = {(- 7 + \frac{x}{7})}^{5}$

Schritt 3.5.2

Vereinfache die rechte Seite.

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Schritt 3.5.2.1

Vereinfache ${(- 7 + \frac{x}{7})}^{5}$ .

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Schritt 3.5.2.1.1

Wende den binomischen Lehrsatz an.

$y = {(- 7)}^{5} + 5 {(- 7)}^{4} \frac{x}{7} + 10 {(- 7)}^{3} {(\frac{x}{7})}^{2} + 10 {(- 7)}^{2} {(\frac{x}{7})}^{3} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2

Vereinfache jeden Term.

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Schritt 3.5.2.1.2.1

Potenziere $- 7$ mit $5$ .

$y = - 16807 + 5 {(- 7)}^{4} \frac{x}{7} + 10 {(- 7)}^{3} {(\frac{x}{7})}^{2} + 10 {(- 7)}^{2} {(\frac{x}{7})}^{3} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.2

Potenziere $- 7$ mit $4$ .

$y = - 16807 + 5 \cdot 2401 \frac{x}{7} + 10 {(- 7)}^{3} {(\frac{x}{7})}^{2} + 10 {(- 7)}^{2} {(\frac{x}{7})}^{3} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.3

Mutltipliziere $5$ mit $2401$ .

$y = - 16807 + 12005 \frac{x}{7} + 10 {(- 7)}^{3} {(\frac{x}{7})}^{2} + 10 {(- 7)}^{2} {(\frac{x}{7})}^{3} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.4

Kürze den gemeinsamen Faktor von $7$ .

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Schritt 3.5.2.1.2.4.1

Faktorisiere $7$ aus $12005$ heraus.

$y = - 16807 + 7 (1715) \frac{x}{7} + 10 {(- 7)}^{3} {(\frac{x}{7})}^{2} + 10 {(- 7)}^{2} {(\frac{x}{7})}^{3} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.4.2

Kürze den gemeinsamen Faktor.

$y = - 16807 + 7 \cdot 1715 \frac{x}{7} + 10 {(- 7)}^{3} {(\frac{x}{7})}^{2} + 10 {(- 7)}^{2} {(\frac{x}{7})}^{3} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.4.3

Forme den Ausdruck um.

$y = - 16807 + 1715 x + 10 {(- 7)}^{3} {(\frac{x}{7})}^{2} + 10 {(- 7)}^{2} {(\frac{x}{7})}^{3} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.5

Potenziere $- 7$ mit $3$ .

$y = - 16807 + 1715 x + 10 \cdot - 343 {(\frac{x}{7})}^{2} + 10 {(- 7)}^{2} {(\frac{x}{7})}^{3} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.6

Mutltipliziere $10$ mit $- 343$ .

$y = - 16807 + 1715 x - 3430 {(\frac{x}{7})}^{2} + 10 {(- 7)}^{2} {(\frac{x}{7})}^{3} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.7

Wende die Produktregel auf $\frac{x}{7}$ an.

$y = - 16807 + 1715 x - 3430 \frac{x^{2}}{7^{2}} + 10 {(- 7)}^{2} {(\frac{x}{7})}^{3} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.8

Potenziere $7$ mit $2$ .

$y = - 16807 + 1715 x - 3430 \frac{x^{2}}{49} + 10 {(- 7)}^{2} {(\frac{x}{7})}^{3} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.9

Kürze den gemeinsamen Faktor von $49$ .

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Schritt 3.5.2.1.2.9.1

Faktorisiere $49$ aus $- 3430$ heraus.

$y = - 16807 + 1715 x + 49 (- 70) \frac{x^{2}}{49} + 10 {(- 7)}^{2} {(\frac{x}{7})}^{3} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.9.2

Kürze den gemeinsamen Faktor.

$y = - 16807 + 1715 x + 49 \cdot - 70 \frac{x^{2}}{49} + 10 {(- 7)}^{2} {(\frac{x}{7})}^{3} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.9.3

Forme den Ausdruck um.

$y = - 16807 + 1715 x - 70 x^{2} + 10 {(- 7)}^{2} {(\frac{x}{7})}^{3} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.10

Potenziere $- 7$ mit $2$ .

$y = - 16807 + 1715 x - 70 x^{2} + 10 \cdot 49 {(\frac{x}{7})}^{3} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.11

Mutltipliziere $10$ mit $49$ .

$y = - 16807 + 1715 x - 70 x^{2} + 490 {(\frac{x}{7})}^{3} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.12

Wende die Produktregel auf $\frac{x}{7}$ an.

$y = - 16807 + 1715 x - 70 x^{2} + 490 \frac{x^{3}}{7^{3}} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.13

Potenziere $7$ mit $3$ .

$y = - 16807 + 1715 x - 70 x^{2} + 490 \frac{x^{3}}{343} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.14

Kürze den gemeinsamen Faktor von $49$ .

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Schritt 3.5.2.1.2.14.1

Faktorisiere $49$ aus $490$ heraus.

$y = - 16807 + 1715 x - 70 x^{2} + 49 (10) \frac{x^{3}}{343} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.14.2

Faktorisiere $49$ aus $343$ heraus.

$y = - 16807 + 1715 x - 70 x^{2} + 49 \cdot 10 \frac{x^{3}}{49 \cdot 7} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.14.3

Kürze den gemeinsamen Faktor.

$y = - 16807 + 1715 x - 70 x^{2} + 49 \cdot 10 \frac{x^{3}}{49 \cdot 7} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.14.4

Forme den Ausdruck um.

$y = - 16807 + 1715 x - 70 x^{2} + 10 \frac{x^{3}}{7} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.15

Kombiniere $10$ und $\frac{x^{3}}{7}$ .

$y = - 16807 + 1715 x - 70 x^{2} + \frac{10 x^{3}}{7} + 5 \cdot - 7 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.16

Mutltipliziere $5$ mit $- 7$ .

$y = - 16807 + 1715 x - 70 x^{2} + \frac{10 x^{3}}{7} - 35 {(\frac{x}{7})}^{4} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.17

Wende die Produktregel auf $\frac{x}{7}$ an.

$y = - 16807 + 1715 x - 70 x^{2} + \frac{10 x^{3}}{7} - 35 \frac{x^{4}}{7^{4}} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.18

Potenziere $7$ mit $4$ .

$y = - 16807 + 1715 x - 70 x^{2} + \frac{10 x^{3}}{7} - 35 \frac{x^{4}}{2401} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.19

Kürze den gemeinsamen Faktor von $7$ .

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Schritt 3.5.2.1.2.19.1

Faktorisiere $7$ aus $- 35$ heraus.

$y = - 16807 + 1715 x - 70 x^{2} + \frac{10 x^{3}}{7} + 7 (- 5) \frac{x^{4}}{2401} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.19.2

Faktorisiere $7$ aus $2401$ heraus.

$y = - 16807 + 1715 x - 70 x^{2} + \frac{10 x^{3}}{7} + 7 \cdot - 5 \frac{x^{4}}{7 \cdot 343} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.19.3

Kürze den gemeinsamen Faktor.

$y = - 16807 + 1715 x - 70 x^{2} + \frac{10 x^{3}}{7} + 7 \cdot - 5 \frac{x^{4}}{7 \cdot 343} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.19.4

Forme den Ausdruck um.

$y = - 16807 + 1715 x - 70 x^{2} + \frac{10 x^{3}}{7} - 5 \frac{x^{4}}{343} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.20

Kombiniere $- 5$ und $\frac{x^{4}}{343}$ .

$y = - 16807 + 1715 x - 70 x^{2} + \frac{10 x^{3}}{7} + \frac{- 5 x^{4}}{343} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.21

Ziehe das Minuszeichen vor den Bruch.

$y = - 16807 + 1715 x - 70 x^{2} + \frac{10 x^{3}}{7} - \frac{5 x^{4}}{343} + {(\frac{x}{7})}^{5}$

Schritt 3.5.2.1.2.22

Wende die Produktregel auf $\frac{x}{7}$ an.

$y = - 16807 + 1715 x - 70 x^{2} + \frac{10 x^{3}}{7} - \frac{5 x^{4}}{343} + \frac{x^{5}}{7^{5}}$

Schritt 3.5.2.1.2.23

Potenziere $7$ mit $5$ .

$y = - 16807 + 1715 x - 70 x^{2} + \frac{10 x^{3}}{7} - \frac{5 x^{4}}{343} + \frac{x^{5}}{16807}$

Schritt 3.6

Vereinfache $- 16807 + 1715 x - 70 x^{2} + \frac{10 x^{3}}{7} - \frac{5 x^{4}}{343} + \frac{x^{5}}{16807}$ .

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Schritt 3.6.1

Bewege $- 16807$ .

$y = 1715 x - 70 x^{2} + \frac{10 x^{3}}{7} - \frac{5 x^{4}}{343} + \frac{x^{5}}{16807} - 16807$

Schritt 3.6.2

Bewege $1715 x$ .

$y = - 70 x^{2} + \frac{10 x^{3}}{7} - \frac{5 x^{4}}{343} + \frac{x^{5}}{16807} + 1715 x - 16807$

Schritt 3.6.3

Bewege $- 70 x^{2}$ .

$y = \frac{10 x^{3}}{7} - \frac{5 x^{4}}{343} + \frac{x^{5}}{16807} - 70 x^{2} + 1715 x - 16807$

Schritt 3.6.4

Bewege $\frac{10 x^{3}}{7}$ .

$y = - \frac{5 x^{4}}{343} + \frac{x^{5}}{16807} + \frac{10 x^{3}}{7} - 70 x^{2} + 1715 x - 16807$

Schritt 3.6.5

Stelle $- \frac{5 x^{4}}{343}$ und $\frac{x^{5}}{16807}$ um.

$y = \frac{x^{5}}{16807} - \frac{5 x^{4}}{343} + \frac{10 x^{3}}{7} - 70 x^{2} + 1715 x - 16807$

Schritt 4

Ersetze $y$ durch $f^{- 1} (x)$ , um die endgültige Lösung anzuzeigen.

$f^{- 1} (x) = \frac{x^{5}}{16807} - \frac{5 x^{4}}{343} + \frac{10 x^{3}}{7} - 70 x^{2} + 1715 x - 16807$

Schritt 5

Überprüfe, ob $f^{- 1} (x) = \frac{x^{5}}{16807} - \frac{5 x^{4}}{343} + \frac{10 x^{3}}{7} - 70 x^{2} + 1715 x - 16807$ die Umkehrfunktion von $f (x) = 7 (x^{\frac{1}{5}} + 7)$ ist.

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Schritt 5.1

Um die inverse Funktion (Umkehrfunktion) zu prüfen, prüfe ob $f^{- 1} (f (x)) = x$ ist und $f (f^{- 1} (x)) = x$ ist.

Schritt 5.2

Berechne $f^{- 1} (f (x))$ .

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Schritt 5.2.1

Bilde die verkettete Ergebnisfunktion.

$f^{- 1} (f (x))$

Schritt 5.2.2

Berechne $f^{- 1} (7 (x^{\frac{1}{5}} + 7))$ durch Einsetzen des Wertes von $f$ in $f^{- 1}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = \frac{{(7 (x^{\frac{1}{5}} + 7))}^{5}}{16807} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3

Vereinfache jeden Term.

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Schritt 5.2.3.1

Vereinfache den Zähler.

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Schritt 5.2.3.1.1

Wende die Produktregel auf $7 (x^{\frac{1}{5}} + 7)$ an.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = \frac{7^{5} {(x^{\frac{1}{5}} + 7)}^{5}}{16807} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.1.2

Potenziere $7$ mit $5$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = \frac{16807 {(x^{\frac{1}{5}} + 7)}^{5}}{16807} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.2

Kürze den gemeinsamen Faktor.

Schritt 5.2.3.3

Dividiere ${(x^{\frac{1}{5}} + 7)}^{5}$ durch $1$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = {(x^{\frac{1}{5}} + 7)}^{5} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.4

Wende den binomischen Lehrsatz an.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = {(x^{\frac{1}{5}})}^{5} + 5 {(x^{\frac{1}{5}})}^{4} \cdot 7 + 10 {(x^{\frac{1}{5}})}^{3} \cdot 7^{2} + 10 {(x^{\frac{1}{5}})}^{2} \cdot 7^{3} + 5 x^{\frac{1}{5}} \cdot 7^{4} + 7^{5} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.5

Vereinfache jeden Term.

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Schritt 5.2.3.5.1

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{5}$ .

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Schritt 5.2.3.5.1.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x^{\frac{1}{5} \cdot 5} + 5 {(x^{\frac{1}{5}})}^{4} \cdot 7 + 10 {(x^{\frac{1}{5}})}^{3} \cdot 7^{2} + 10 {(x^{\frac{1}{5}})}^{2} \cdot 7^{3} + 5 x^{\frac{1}{5}} \cdot 7^{4} + 7^{5} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.5.1.2

Kürze den gemeinsamen Faktor von $5$ .

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Schritt 5.2.3.5.1.2.1

Kürze den gemeinsamen Faktor.

Schritt 5.2.3.5.1.2.2

Forme den Ausdruck um.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 5 {(x^{\frac{1}{5}})}^{4} \cdot 7 + 10 {(x^{\frac{1}{5}})}^{3} \cdot 7^{2} + 10 {(x^{\frac{1}{5}})}^{2} \cdot 7^{3} + 5 x^{\frac{1}{5}} \cdot 7^{4} + 7^{5} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.5.2

Vereinfache.

Schritt 5.2.3.5.3

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{4}$ .

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Schritt 5.2.3.5.3.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 5 x^{\frac{1}{5} \cdot 4} \cdot 7 + 10 {(x^{\frac{1}{5}})}^{3} \cdot 7^{2} + 10 {(x^{\frac{1}{5}})}^{2} \cdot 7^{3} + 5 x^{\frac{1}{5}} \cdot 7^{4} + 7^{5} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.5.3.2

Kombiniere $\frac{1}{5}$ und $4$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 5 x^{\frac{4}{5}} \cdot 7 + 10 {(x^{\frac{1}{5}})}^{3} \cdot 7^{2} + 10 {(x^{\frac{1}{5}})}^{2} \cdot 7^{3} + 5 x^{\frac{1}{5}} \cdot 7^{4} + 7^{5} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.5.4

Mutltipliziere $7$ mit $5$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 10 {(x^{\frac{1}{5}})}^{3} \cdot 7^{2} + 10 {(x^{\frac{1}{5}})}^{2} \cdot 7^{3} + 5 x^{\frac{1}{5}} \cdot 7^{4} + 7^{5} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.5.5

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{3}$ .

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Schritt 5.2.3.5.5.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 10 x^{\frac{1}{5} \cdot 3} \cdot 7^{2} + 10 {(x^{\frac{1}{5}})}^{2} \cdot 7^{3} + 5 x^{\frac{1}{5}} \cdot 7^{4} + 7^{5} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.5.5.2

Kombiniere $\frac{1}{5}$ und $3$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} \cdot 7^{2} + 10 {(x^{\frac{1}{5}})}^{2} \cdot 7^{3} + 5 x^{\frac{1}{5}} \cdot 7^{4} + 7^{5} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.5.6

Potenziere $7$ mit $2$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} \cdot 49 + 10 {(x^{\frac{1}{5}})}^{2} \cdot 7^{3} + 5 x^{\frac{1}{5}} \cdot 7^{4} + 7^{5} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.5.7

Mutltipliziere $49$ mit $10$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 10 {(x^{\frac{1}{5}})}^{2} \cdot 7^{3} + 5 x^{\frac{1}{5}} \cdot 7^{4} + 7^{5} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.5.8

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{2}$ .

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Schritt 5.2.3.5.8.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 10 x^{\frac{1}{5} \cdot 2} \cdot 7^{3} + 5 x^{\frac{1}{5}} \cdot 7^{4} + 7^{5} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.5.8.2

Kombiniere $\frac{1}{5}$ und $2$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 10 x^{\frac{2}{5}} \cdot 7^{3} + 5 x^{\frac{1}{5}} \cdot 7^{4} + 7^{5} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.5.9

Potenziere $7$ mit $3$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 10 x^{\frac{2}{5}} \cdot 343 + 5 x^{\frac{1}{5}} \cdot 7^{4} + 7^{5} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.5.10

Mutltipliziere $343$ mit $10$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} \cdot 7^{4} + 7^{5} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.5.11

Potenziere $7$ mit $4$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} \cdot 2401 + 7^{5} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.5.12

Mutltipliziere $2401$ mit $5$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 7^{5} - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.5.13

Potenziere $7$ mit $5$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - \frac{5 {(7 (x^{\frac{1}{5}} + 7))}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.6

Vereinfache den Zähler.

Tippen, um mehr Schritte zu sehen ...

Schritt 5.2.3.6.1

Wende die Produktregel auf $7 (x^{\frac{1}{5}} + 7)$ an.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - \frac{5 \cdot (7^{4} {(x^{\frac{1}{5}} + 7)}^{4})}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.6.2

Potenziere $7$ mit $4$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - \frac{5 \cdot (2401 {(x^{\frac{1}{5}} + 7)}^{4})}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.6.3

Mutltipliziere $5$ mit $2401$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - \frac{12005 {(x^{\frac{1}{5}} + 7)}^{4}}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.7

Faktorisiere $343$ aus $12005 {(x^{\frac{1}{5}} + 7)}^{4}$ heraus.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - \frac{343 (35 {(x^{\frac{1}{5}} + 7)}^{4})}{343} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.8

Kürze die gemeinsamen Faktoren.

Tippen, um mehr Schritte zu sehen ...

Schritt 5.2.3.8.1

Faktorisiere $343$ aus $343$ heraus.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - \frac{343 (35 {(x^{\frac{1}{5}} + 7)}^{4})}{343 (1)} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.8.2

Kürze den gemeinsamen Faktor.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - \frac{343 (35 {(x^{\frac{1}{5}} + 7)}^{4})}{343 \cdot 1} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.8.3

Forme den Ausdruck um.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - \frac{35 {(x^{\frac{1}{5}} + 7)}^{4}}{1} + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.8.4

Dividiere $35 {(x^{\frac{1}{5}} + 7)}^{4}$ durch $1$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 {(x^{\frac{1}{5}} + 7)}^{4}) + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.9

Wende den binomischen Lehrsatz an.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 ({(x^{\frac{1}{5}})}^{4} + 4 {(x^{\frac{1}{5}})}^{3} \cdot 7 + 6 {(x^{\frac{1}{5}})}^{2} \cdot 7^{2} + 4 x^{\frac{1}{5}} \cdot 7^{3} + 7^{4})) + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.10

Vereinfache jeden Term.

Tippen, um mehr Schritte zu sehen ...

Schritt 5.2.3.10.1

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{4}$ .

Tippen, um mehr Schritte zu sehen ...

Schritt 5.2.3.10.1.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 (x^{\frac{1}{5} \cdot 4} + 4 {(x^{\frac{1}{5}})}^{3} \cdot 7 + 6 {(x^{\frac{1}{5}})}^{2} \cdot 7^{2} + 4 x^{\frac{1}{5}} \cdot 7^{3} + 7^{4})) + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.10.1.2

Kombiniere $\frac{1}{5}$ und $4$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 (x^{\frac{4}{5}} + 4 {(x^{\frac{1}{5}})}^{3} \cdot 7 + 6 {(x^{\frac{1}{5}})}^{2} \cdot 7^{2} + 4 x^{\frac{1}{5}} \cdot 7^{3} + 7^{4})) + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.10.2

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{3}$ .

Tippen, um mehr Schritte zu sehen ...

Schritt 5.2.3.10.2.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 (x^{\frac{4}{5}} + 4 x^{\frac{1}{5} \cdot 3} \cdot 7 + 6 {(x^{\frac{1}{5}})}^{2} \cdot 7^{2} + 4 x^{\frac{1}{5}} \cdot 7^{3} + 7^{4})) + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.10.2.2

Kombiniere $\frac{1}{5}$ und $3$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 (x^{\frac{4}{5}} + 4 x^{\frac{3}{5}} \cdot 7 + 6 {(x^{\frac{1}{5}})}^{2} \cdot 7^{2} + 4 x^{\frac{1}{5}} \cdot 7^{3} + 7^{4})) + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.10.3

Mutltipliziere $7$ mit $4$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 (x^{\frac{4}{5}} + 28 x^{\frac{3}{5}} + 6 {(x^{\frac{1}{5}})}^{2} \cdot 7^{2} + 4 x^{\frac{1}{5}} \cdot 7^{3} + 7^{4})) + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.10.4

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{2}$ .

Tippen, um mehr Schritte zu sehen ...

Schritt 5.2.3.10.4.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 (x^{\frac{4}{5}} + 28 x^{\frac{3}{5}} + 6 x^{\frac{1}{5} \cdot 2} \cdot 7^{2} + 4 x^{\frac{1}{5}} \cdot 7^{3} + 7^{4})) + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.10.4.2

Kombiniere $\frac{1}{5}$ und $2$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 (x^{\frac{4}{5}} + 28 x^{\frac{3}{5}} + 6 x^{\frac{2}{5}} \cdot 7^{2} + 4 x^{\frac{1}{5}} \cdot 7^{3} + 7^{4})) + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.10.5

Potenziere $7$ mit $2$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 (x^{\frac{4}{5}} + 28 x^{\frac{3}{5}} + 6 x^{\frac{2}{5}} \cdot 49 + 4 x^{\frac{1}{5}} \cdot 7^{3} + 7^{4})) + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.10.6

Mutltipliziere $49$ mit $6$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 (x^{\frac{4}{5}} + 28 x^{\frac{3}{5}} + 294 x^{\frac{2}{5}} + 4 x^{\frac{1}{5}} \cdot 7^{3} + 7^{4})) + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.10.7

Potenziere $7$ mit $3$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 (x^{\frac{4}{5}} + 28 x^{\frac{3}{5}} + 294 x^{\frac{2}{5}} + 4 x^{\frac{1}{5}} \cdot 343 + 7^{4})) + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.10.8

Mutltipliziere $343$ mit $4$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 (x^{\frac{4}{5}} + 28 x^{\frac{3}{5}} + 294 x^{\frac{2}{5}} + 1372 x^{\frac{1}{5}} + 7^{4})) + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.10.9

Potenziere $7$ mit $4$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 (x^{\frac{4}{5}} + 28 x^{\frac{3}{5}} + 294 x^{\frac{2}{5}} + 1372 x^{\frac{1}{5}} + 2401)) + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.11

Wende das Distributivgesetz an.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 x^{\frac{4}{5}} + 35 (28 x^{\frac{3}{5}}) + 35 (294 x^{\frac{2}{5}}) + 35 (1372 x^{\frac{1}{5}}) + 35 \cdot 2401) + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.12

Vereinfache.

Tippen, um mehr Schritte zu sehen ...

Schritt 5.2.3.12.1

Mutltipliziere $28$ mit $35$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 x^{\frac{4}{5}} + 980 x^{\frac{3}{5}} + 35 (294 x^{\frac{2}{5}}) + 35 (1372 x^{\frac{1}{5}}) + 35 \cdot 2401) + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.12.2

Mutltipliziere $294$ mit $35$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 x^{\frac{4}{5}} + 980 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 35 (1372 x^{\frac{1}{5}}) + 35 \cdot 2401) + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.12.3

Mutltipliziere $1372$ mit $35$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 x^{\frac{4}{5}} + 980 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 48020 x^{\frac{1}{5}} + 35 \cdot 2401) + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.12.4

Mutltipliziere $35$ mit $2401$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 x^{\frac{4}{5}} + 980 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 48020 x^{\frac{1}{5}} + 84035) + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.13

Wende das Distributivgesetz an.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - (35 x^{\frac{4}{5}}) - (980 x^{\frac{3}{5}}) - (10290 x^{\frac{2}{5}}) - (48020 x^{\frac{1}{5}}) - 1 \cdot 84035 + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.14

Vereinfache.

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Schritt 5.2.3.14.1

Mutltipliziere $35$ mit $- 1$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - (980 x^{\frac{3}{5}}) - (10290 x^{\frac{2}{5}}) - (48020 x^{\frac{1}{5}}) - 1 \cdot 84035 + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.14.2

Mutltipliziere $980$ mit $- 1$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - (10290 x^{\frac{2}{5}}) - (48020 x^{\frac{1}{5}}) - 1 \cdot 84035 + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.14.3

Mutltipliziere $10290$ mit $- 1$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - (48020 x^{\frac{1}{5}}) - 1 \cdot 84035 + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.14.4

Mutltipliziere $48020$ mit $- 1$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 1 \cdot 84035 + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.14.5

Mutltipliziere $- 1$ mit $84035$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + \frac{10 {(7 (x^{\frac{1}{5}} + 7))}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.15

Vereinfache den Zähler.

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Schritt 5.2.3.15.1

Wende die Produktregel auf $7 (x^{\frac{1}{5}} + 7)$ an.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + \frac{10 \cdot (7^{3} {(x^{\frac{1}{5}} + 7)}^{3})}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.15.2

Potenziere $7$ mit $3$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + \frac{10 \cdot (343 {(x^{\frac{1}{5}} + 7)}^{3})}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.15.3

Mutltipliziere $10$ mit $343$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + \frac{3430 {(x^{\frac{1}{5}} + 7)}^{3}}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.16

Faktorisiere $7$ aus $3430 {(x^{\frac{1}{5}} + 7)}^{3}$ heraus.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + \frac{7 (490 {(x^{\frac{1}{5}} + 7)}^{3})}{7} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.17

Kürze die gemeinsamen Faktoren.

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Schritt 5.2.3.17.1

Faktorisiere $7$ aus $7$ heraus.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + \frac{7 (490 {(x^{\frac{1}{5}} + 7)}^{3})}{7 (1)} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.17.2

Kürze den gemeinsamen Faktor.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + \frac{7 (490 {(x^{\frac{1}{5}} + 7)}^{3})}{7 \cdot 1} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.17.3

Forme den Ausdruck um.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + \frac{490 {(x^{\frac{1}{5}} + 7)}^{3}}{1} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.17.4

Dividiere $490 {(x^{\frac{1}{5}} + 7)}^{3}$ durch $1$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 {(x^{\frac{1}{5}} + 7)}^{3} - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.18

Wende den binomischen Lehrsatz an.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 ({(x^{\frac{1}{5}})}^{3} + 3 {(x^{\frac{1}{5}})}^{2} \cdot 7 + 3 x^{\frac{1}{5}} \cdot 7^{2} + 7^{3}) - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.19

Vereinfache jeden Term.

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Schritt 5.2.3.19.1

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{3}$ .

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Schritt 5.2.3.19.1.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 (x^{\frac{1}{5} \cdot 3} + 3 {(x^{\frac{1}{5}})}^{2} \cdot 7 + 3 x^{\frac{1}{5}} \cdot 7^{2} + 7^{3}) - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.19.1.2

Kombiniere $\frac{1}{5}$ und $3$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 (x^{\frac{3}{5}} + 3 {(x^{\frac{1}{5}})}^{2} \cdot 7 + 3 x^{\frac{1}{5}} \cdot 7^{2} + 7^{3}) - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.19.2

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{2}$ .

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Schritt 5.2.3.19.2.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 (x^{\frac{3}{5}} + 3 x^{\frac{1}{5} \cdot 2} \cdot 7 + 3 x^{\frac{1}{5}} \cdot 7^{2} + 7^{3}) - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.19.2.2

Kombiniere $\frac{1}{5}$ und $2$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 (x^{\frac{3}{5}} + 3 x^{\frac{2}{5}} \cdot 7 + 3 x^{\frac{1}{5}} \cdot 7^{2} + 7^{3}) - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.19.3

Mutltipliziere $7$ mit $3$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 (x^{\frac{3}{5}} + 21 x^{\frac{2}{5}} + 3 x^{\frac{1}{5}} \cdot 7^{2} + 7^{3}) - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.19.4

Potenziere $7$ mit $2$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 (x^{\frac{3}{5}} + 21 x^{\frac{2}{5}} + 3 x^{\frac{1}{5}} \cdot 49 + 7^{3}) - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.19.5

Mutltipliziere $49$ mit $3$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 (x^{\frac{3}{5}} + 21 x^{\frac{2}{5}} + 147 x^{\frac{1}{5}} + 7^{3}) - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.19.6

Potenziere $7$ mit $3$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 (x^{\frac{3}{5}} + 21 x^{\frac{2}{5}} + 147 x^{\frac{1}{5}} + 343) - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.20

Wende das Distributivgesetz an.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 490 (21 x^{\frac{2}{5}}) + 490 (147 x^{\frac{1}{5}}) + 490 \cdot 343 - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.21

Vereinfache.

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Schritt 5.2.3.21.1

Mutltipliziere $21$ mit $490$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 490 (147 x^{\frac{1}{5}}) + 490 \cdot 343 - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.21.2

Mutltipliziere $147$ mit $490$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 490 \cdot 343 - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.21.3

Mutltipliziere $490$ mit $343$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 70 {(7 (x^{\frac{1}{5}} + 7))}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.22

Wende das Distributivgesetz an.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 70 {(7 x^{\frac{1}{5}} + 7 \cdot 7)}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.23

Mutltipliziere $7$ mit $7$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 70 {(7 x^{\frac{1}{5}} + 49)}^{2} + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.24

Schreibe ${(7 x^{\frac{1}{5}} + 49)}^{2}$ als $(7 x^{\frac{1}{5}} + 49) (7 x^{\frac{1}{5}} + 49)$ um.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 70 ((7 x^{\frac{1}{5}} + 49) (7 x^{\frac{1}{5}} + 49)) + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.25

Multipliziere $(7 x^{\frac{1}{5}} + 49) (7 x^{\frac{1}{5}} + 49)$ aus unter Verwendung der FOIL-Methode.

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Schritt 5.2.3.25.1

Wende das Distributivgesetz an.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 70 (7 x^{\frac{1}{5}} (7 x^{\frac{1}{5}} + 49) + 49 (7 x^{\frac{1}{5}} + 49)) + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.25.2

Wende das Distributivgesetz an.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 70 (7 x^{\frac{1}{5}} (7 x^{\frac{1}{5}}) + 7 x^{\frac{1}{5}} \cdot 49 + 49 (7 x^{\frac{1}{5}} + 49)) + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.25.3

Wende das Distributivgesetz an.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 70 (7 x^{\frac{1}{5}} (7 x^{\frac{1}{5}}) + 7 x^{\frac{1}{5}} \cdot 49 + 49 (7 x^{\frac{1}{5}}) + 49 \cdot 49) + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.26

Vereinfache und fasse gleichartige Terme zusammen.

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Schritt 5.2.3.26.1

Vereinfache jeden Term.

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Schritt 5.2.3.26.1.1

Schreibe neu unter Anwendung des Kommutativgesetzes der Multiplikation.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 70 (7 \cdot (7 x^{\frac{1}{5}} x^{\frac{1}{5}}) + 7 x^{\frac{1}{5}} \cdot 49 + 49 (7 x^{\frac{1}{5}}) + 49 \cdot 49) + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.26.1.2

Multipliziere $x^{\frac{1}{5}}$ mit $x^{\frac{1}{5}}$ durch Addieren der Exponenten.

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Schritt 5.2.3.26.1.2.1

Bewege $x^{\frac{1}{5}}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 70 (7 \cdot (7 (x^{\frac{1}{5}} x^{\frac{1}{5}})) + 7 x^{\frac{1}{5}} \cdot 49 + 49 (7 x^{\frac{1}{5}}) + 49 \cdot 49) + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.26.1.2.2

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 70 (7 \cdot (7 x^{\frac{1}{5} + \frac{1}{5}}) + 7 x^{\frac{1}{5}} \cdot 49 + 49 (7 x^{\frac{1}{5}}) + 49 \cdot 49) + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.26.1.2.3

Vereinige die Zähler über dem gemeinsamen Nenner.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 70 (7 \cdot (7 x^{\frac{1 + 1}{5}}) + 7 x^{\frac{1}{5}} \cdot 49 + 49 (7 x^{\frac{1}{5}}) + 49 \cdot 49) + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.26.1.2.4

Addiere $1$ und $1$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 70 (7 \cdot (7 x^{\frac{2}{5}}) + 7 x^{\frac{1}{5}} \cdot 49 + 49 (7 x^{\frac{1}{5}}) + 49 \cdot 49) + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.26.1.3

Mutltipliziere $7$ mit $7$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 70 (49 x^{\frac{2}{5}} + 7 x^{\frac{1}{5}} \cdot 49 + 49 (7 x^{\frac{1}{5}}) + 49 \cdot 49) + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.26.1.4

Mutltipliziere $49$ mit $7$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 70 (49 x^{\frac{2}{5}} + 343 x^{\frac{1}{5}} + 49 (7 x^{\frac{1}{5}}) + 49 \cdot 49) + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.26.1.5

Mutltipliziere $7$ mit $49$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 70 (49 x^{\frac{2}{5}} + 343 x^{\frac{1}{5}} + 343 x^{\frac{1}{5}} + 49 \cdot 49) + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.26.1.6

Mutltipliziere $49$ mit $49$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 70 (49 x^{\frac{2}{5}} + 343 x^{\frac{1}{5}} + 343 x^{\frac{1}{5}} + 2401) + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.26.2

Addiere $343 x^{\frac{1}{5}}$ und $343 x^{\frac{1}{5}}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 70 (49 x^{\frac{2}{5}} + 686 x^{\frac{1}{5}} + 2401) + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.27

Wende das Distributivgesetz an.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 70 (49 x^{\frac{2}{5}}) - 70 (686 x^{\frac{1}{5}}) - 70 \cdot 2401 + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.28

Vereinfache.

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Schritt 5.2.3.28.1

Mutltipliziere $49$ mit $- 70$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 3430 x^{\frac{2}{5}} - 70 (686 x^{\frac{1}{5}}) - 70 \cdot 2401 + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.28.2

Mutltipliziere $686$ mit $- 70$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 3430 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 70 \cdot 2401 + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.28.3

Mutltipliziere $- 70$ mit $2401$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 3430 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 168070 + 1715 (7 (x^{\frac{1}{5}} + 7)) - 16807$

Schritt 5.2.3.29

Wende das Distributivgesetz an.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 3430 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 168070 + 1715 (7 x^{\frac{1}{5}} + 7 \cdot 7) - 16807$

Schritt 5.2.3.30

Mutltipliziere $7$ mit $7$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 3430 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 168070 + 1715 (7 x^{\frac{1}{5}} + 49) - 16807$

Schritt 5.2.3.31

Wende das Distributivgesetz an.

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 3430 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 168070 + 1715 (7 x^{\frac{1}{5}}) + 1715 \cdot 49 - 16807$

Schritt 5.2.3.32

Mutltipliziere $7$ mit $1715$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 3430 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 168070 + 12005 x^{\frac{1}{5}} + 1715 \cdot 49 - 16807$

Schritt 5.2.3.33

Mutltipliziere $1715$ mit $49$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 3430 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 168070 + 12005 x^{\frac{1}{5}} + 84035 - 16807$

Schritt 5.2.4

Vereinfache durch Addieren von Termen.

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Schritt 5.2.4.1

Vereine die Terme mit entgegengesetztem Vorzeichen in $x + 35 x^{\frac{4}{5}} + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 35 x^{\frac{4}{5}} - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 3430 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 168070 + 12005 x^{\frac{1}{5}} + 84035 - 16807$ .

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Schritt 5.2.4.1.1

Subtrahiere $35 x^{\frac{4}{5}}$ von $35 x^{\frac{4}{5}}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 + 0 - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 3430 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 168070 + 12005 x^{\frac{1}{5}} + 84035 - 16807$

Schritt 5.2.4.1.2

Addiere $x + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807$ und $0$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 980 x^{\frac{3}{5}} - 10290 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 10290 x^{\frac{2}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 3430 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 168070 + 12005 x^{\frac{1}{5}} + 84035 - 16807$

Schritt 5.2.4.1.3

Addiere $- 10290 x^{\frac{2}{5}}$ und $10290 x^{\frac{2}{5}}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 980 x^{\frac{3}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 0 + 72030 x^{\frac{1}{5}} + 168070 - 3430 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 168070 + 12005 x^{\frac{1}{5}} + 84035 - 16807$

Schritt 5.2.4.1.4

Addiere $x + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 980 x^{\frac{3}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}}$ und $0$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 490 x^{\frac{3}{5}} + 3430 x^{\frac{2}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 980 x^{\frac{3}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 3430 x^{\frac{2}{5}} - 48020 x^{\frac{1}{5}} - 168070 + 12005 x^{\frac{1}{5}} + 84035 - 16807$

Schritt 5.2.4.1.5

Subtrahiere $3430 x^{\frac{2}{5}}$ von $3430 x^{\frac{2}{5}}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 490 x^{\frac{3}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 980 x^{\frac{3}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 72030 x^{\frac{1}{5}} + 168070 + 0 - 48020 x^{\frac{1}{5}} - 168070 + 12005 x^{\frac{1}{5}} + 84035 - 16807$

Schritt 5.2.4.1.6

Addiere $x + 490 x^{\frac{3}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 980 x^{\frac{3}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 72030 x^{\frac{1}{5}} + 168070$ und $0$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 490 x^{\frac{3}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 980 x^{\frac{3}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 72030 x^{\frac{1}{5}} + 168070 - 48020 x^{\frac{1}{5}} - 168070 + 12005 x^{\frac{1}{5}} + 84035 - 16807$

Schritt 5.2.4.1.7

Subtrahiere $168070$ von $168070$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 490 x^{\frac{3}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 980 x^{\frac{3}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 72030 x^{\frac{1}{5}} - 48020 x^{\frac{1}{5}} + 0 + 12005 x^{\frac{1}{5}} + 84035 - 16807$

Schritt 5.2.4.1.8

Addiere $x + 490 x^{\frac{3}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 980 x^{\frac{3}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 72030 x^{\frac{1}{5}} - 48020 x^{\frac{1}{5}}$ und $0$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 490 x^{\frac{3}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 980 x^{\frac{3}{5}} - 48020 x^{\frac{1}{5}} - 84035 + 490 x^{\frac{3}{5}} + 72030 x^{\frac{1}{5}} - 48020 x^{\frac{1}{5}} + 12005 x^{\frac{1}{5}} + 84035 - 16807$

Schritt 5.2.4.1.9

Addiere $- 84035$ und $84035$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 490 x^{\frac{3}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 980 x^{\frac{3}{5}} - 48020 x^{\frac{1}{5}} + 490 x^{\frac{3}{5}} + 72030 x^{\frac{1}{5}} - 48020 x^{\frac{1}{5}} + 12005 x^{\frac{1}{5}} + 0 - 16807$

Schritt 5.2.4.1.10

Addiere $x + 490 x^{\frac{3}{5}} + 12005 x^{\frac{1}{5}} + 16807 - 980 x^{\frac{3}{5}} - 48020 x^{\frac{1}{5}} + 490 x^{\frac{3}{5}} + 72030 x^{\frac{1}{5}} - 48020 x^{\frac{1}{5}} + 12005 x^{\frac{1}{5}}$ und $0$ .

Schritt 5.2.4.1.11

Subtrahiere $16807$ von $16807$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 490 x^{\frac{3}{5}} + 12005 x^{\frac{1}{5}} - 980 x^{\frac{3}{5}} - 48020 x^{\frac{1}{5}} + 490 x^{\frac{3}{5}} + 72030 x^{\frac{1}{5}} - 48020 x^{\frac{1}{5}} + 12005 x^{\frac{1}{5}} + 0$

Schritt 5.2.4.1.12

Addiere $x + 490 x^{\frac{3}{5}} + 12005 x^{\frac{1}{5}} - 980 x^{\frac{3}{5}} - 48020 x^{\frac{1}{5}} + 490 x^{\frac{3}{5}} + 72030 x^{\frac{1}{5}} - 48020 x^{\frac{1}{5}} + 12005 x^{\frac{1}{5}}$ und $0$ .

Schritt 5.2.4.2

Subtrahiere $980 x^{\frac{3}{5}}$ von $490 x^{\frac{3}{5}}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 12005 x^{\frac{1}{5}} - 490 x^{\frac{3}{5}} - 48020 x^{\frac{1}{5}} + 490 x^{\frac{3}{5}} + 72030 x^{\frac{1}{5}} - 48020 x^{\frac{1}{5}} + 12005 x^{\frac{1}{5}}$

Schritt 5.2.4.3

Vereine die Terme mit entgegengesetztem Vorzeichen in $x + 12005 x^{\frac{1}{5}} - 490 x^{\frac{3}{5}} - 48020 x^{\frac{1}{5}} + 490 x^{\frac{3}{5}} + 72030 x^{\frac{1}{5}} - 48020 x^{\frac{1}{5}} + 12005 x^{\frac{1}{5}}$ .

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Schritt 5.2.4.3.1

Addiere $- 490 x^{\frac{3}{5}}$ und $490 x^{\frac{3}{5}}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 12005 x^{\frac{1}{5}} - 48020 x^{\frac{1}{5}} + 0 + 72030 x^{\frac{1}{5}} - 48020 x^{\frac{1}{5}} + 12005 x^{\frac{1}{5}}$

Schritt 5.2.4.3.2

Addiere $x + 12005 x^{\frac{1}{5}} - 48020 x^{\frac{1}{5}}$ und $0$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 12005 x^{\frac{1}{5}} - 48020 x^{\frac{1}{5}} + 72030 x^{\frac{1}{5}} - 48020 x^{\frac{1}{5}} + 12005 x^{\frac{1}{5}}$

Schritt 5.2.4.4

Subtrahiere $48020 x^{\frac{1}{5}}$ von $12005 x^{\frac{1}{5}}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x - 36015 x^{\frac{1}{5}} + 72030 x^{\frac{1}{5}} - 48020 x^{\frac{1}{5}} + 12005 x^{\frac{1}{5}}$

Schritt 5.2.4.5

Addiere $- 36015 x^{\frac{1}{5}}$ und $72030 x^{\frac{1}{5}}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 36015 x^{\frac{1}{5}} - 48020 x^{\frac{1}{5}} + 12005 x^{\frac{1}{5}}$

Schritt 5.2.4.6

Subtrahiere $48020 x^{\frac{1}{5}}$ von $36015 x^{\frac{1}{5}}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x - 12005 x^{\frac{1}{5}} + 12005 x^{\frac{1}{5}}$

Schritt 5.2.4.7

Vereine die Terme mit entgegengesetztem Vorzeichen in $x - 12005 x^{\frac{1}{5}} + 12005 x^{\frac{1}{5}}$ .

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Schritt 5.2.4.7.1

Addiere $- 12005 x^{\frac{1}{5}}$ und $12005 x^{\frac{1}{5}}$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x + 0$

Schritt 5.2.4.7.2

Addiere $x$ und $0$ .

$f^{- 1} (7 (x^{\frac{1}{5}} + 7)) = x$

Schritt 5.3

Berechne $f (f^{- 1} (x))$ .

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Schritt 5.3.1

Bilde die verkettete Ergebnisfunktion.

$f (f^{- 1} (x))$

Schritt 5.3.2

Berechne $f (\frac{x^{5}}{16807} - \frac{5 x^{4}}{343} + \frac{10 x^{3}}{7} - 70 x^{2} + 1715 x - 16807)$ durch Einsetzen des Wertes von $f^{- 1}$ in $f$ .

$f (\frac{x^{5}}{16807} - \frac{5 x^{4}}{343} + \frac{10 x^{3}}{7} - 70 x^{2} + 1715 x - 16807) = 7 ({(\frac{x^{5}}{16807} - \frac{5 x^{4}}{343} + \frac{10 x^{3}}{7} - 70 x^{2} + 1715 x - 16807)}^{\frac{1}{5}} + 7)$

Schritt 5.3.3

Wende das Distributivgesetz an.

$f (\frac{x^{5}}{16807} - \frac{5 x^{4}}{343} + \frac{10 x^{3}}{7} - 70 x^{2} + 1715 x - 16807) = 7 {(\frac{x^{5}}{16807} - \frac{5 x^{4}}{343} + \frac{10 x^{3}}{7} - 70 x^{2} + 1715 x - 16807)}^{\frac{1}{5}} + 7 \cdot 7$

Schritt 5.3.4

Mutltipliziere $7$ mit $7$ .

Schritt 5.4

Da $f^{- 1} (f (x)) = x$ und $f (f^{- 1} (x)) = x$ gleich sind, ist $f^{- 1} (x) = \frac{x^{5}}{16807} - \frac{5 x^{4}}{343} + \frac{10 x^{3}}{7} - 70 x^{2} + 1715 x - 16807$ die inverse Funktion (Umkehrfunktion) von $f (x) = 7 (x^{\frac{1}{5}} + 7)$ .

$f^{- 1} (x) = \frac{x^{5}}{16807} - \frac{5 x^{4}}{343} + \frac{10 x^{3}}{7} - 70 x^{2} + 1715 x - 16807$