Elementarmathematik Beispiele

$f (x) = 2 x^{\frac{1}{5}} - 2$ ; find $f^{- 1} (x)$

Schritt 1

Ermittle $f^{- 1} (x)$ .

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Schritt 1.1

Schreibe $f (x) = 2 x^{\frac{1}{5}} - 2$ als Gleichung.

$y = 2 x^{\frac{1}{5}} - 2$

Schritt 1.2

Vertausche die Variablen.

$x = 2 y^{\frac{1}{5}} - 2$

Schritt 1.3

Löse nach $y$ auf.

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Schritt 1.3.1

Schreibe die Gleichung als $2 y^{\frac{1}{5}} - 2 = x$ um.

$2 y^{\frac{1}{5}} - 2 = x$

Schritt 1.3.2

Bringe alle Terme, die nicht $y$ enthalten, auf die rechte Seite der Gleichung.

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Schritt 1.3.2.1

Addiere $2$ zu beiden Seiten der Gleichung.

$2 y^{\frac{1}{5}} - x = 2$

Schritt 1.3.2.2

Addiere $x$ zu beiden Seiten der Gleichung.

$2 y^{\frac{1}{5}} = 2 + x$

Schritt 1.3.3

Potenziere jede Seite der Gleichung mit $5$ , um den gebrochenen Exponenten auf der linken Seite zu eliminieren.

${(2 y^{\frac{1}{5}})}^{5} = {(2 + x)}^{5}$

Schritt 1.3.4

Vereinfache den Exponenten.

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Schritt 1.3.4.1

Vereinfache die linke Seite.

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Schritt 1.3.4.1.1

Vereinfache ${(2 y^{\frac{1}{5}})}^{5}$ .

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Schritt 1.3.4.1.1.1

Wende die Produktregel auf $2 y^{\frac{1}{5}}$ an.

$2^{5} {(y^{\frac{1}{5}})}^{5} = {(2 + x)}^{5}$

Schritt 1.3.4.1.1.2

Potenziere $2$ mit $5$ .

$32 {(y^{\frac{1}{5}})}^{5} = {(2 + x)}^{5}$

Schritt 1.3.4.1.1.3

Multipliziere die Exponenten in ${(y^{\frac{1}{5}})}^{5}$ .

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Schritt 1.3.4.1.1.3.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$32 y^{\frac{1}{5} \cdot 5} = {(2 + x)}^{5}$

Schritt 1.3.4.1.1.3.2

Kürze den gemeinsamen Faktor von $5$ .

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Schritt 1.3.4.1.1.3.2.1

Kürze den gemeinsamen Faktor.

$32 y^{\frac{1}{5} \cdot 5} = {(2 + x)}^{5}$

Schritt 1.3.4.1.1.3.2.2

Forme den Ausdruck um.

$32 y^{1} = {(2 + x)}^{5}$

Schritt 1.3.4.1.1.4

Vereinfache.

$32 y = {(2 + x)}^{5}$

Schritt 1.3.4.2

Vereinfache die rechte Seite.

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Schritt 1.3.4.2.1

Vereinfache ${(2 + x)}^{5}$ .

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Schritt 1.3.4.2.1.1

Wende den binomischen Lehrsatz an.

$32 y = 2^{5} + 5 \cdot 2^{4} x + 10 \cdot 2^{3} x^{2} + 10 \cdot 2^{2} x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Schritt 1.3.4.2.1.2

Vereinfache jeden Term.

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Schritt 1.3.4.2.1.2.1

Potenziere $2$ mit $5$ .

$32 y = 32 + 5 \cdot 2^{4} x + 10 \cdot 2^{3} x^{2} + 10 \cdot 2^{2} x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Schritt 1.3.4.2.1.2.2

Potenziere $2$ mit $4$ .

$32 y = 32 + 5 \cdot 16 x + 10 \cdot 2^{3} x^{2} + 10 \cdot 2^{2} x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Schritt 1.3.4.2.1.2.3

Mutltipliziere $5$ mit $16$ .

$32 y = 32 + 80 x + 10 \cdot 2^{3} x^{2} + 10 \cdot 2^{2} x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Schritt 1.3.4.2.1.2.4

Potenziere $2$ mit $3$ .

$32 y = 32 + 80 x + 10 \cdot 8 x^{2} + 10 \cdot 2^{2} x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Schritt 1.3.4.2.1.2.5

Mutltipliziere $10$ mit $8$ .

$32 y = 32 + 80 x + 80 x^{2} + 10 \cdot 2^{2} x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Schritt 1.3.4.2.1.2.6

Potenziere $2$ mit $2$ .

$32 y = 32 + 80 x + 80 x^{2} + 10 \cdot 4 x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Schritt 1.3.4.2.1.2.7

Mutltipliziere $10$ mit $4$ .

$32 y = 32 + 80 x + 80 x^{2} + 40 x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Schritt 1.3.4.2.1.2.8

Mutltipliziere $5$ mit $2$ .

$32 y = 32 + 80 x + 80 x^{2} + 40 x^{3} + 10 x^{4} + x^{5}$

Schritt 1.3.5

Teile jeden Ausdruck in $32 y = 32 + 80 x + 80 x^{2} + 40 x^{3} + 10 x^{4} + x^{5}$ durch $32$ und vereinfache.

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Schritt 1.3.5.1

Teile jeden Ausdruck in $32 y = 32 + 80 x + 80 x^{2} + 40 x^{3} + 10 x^{4} + x^{5}$ durch $32$ .

$\frac{32 y}{32} = \frac{32}{32} + \frac{80 x}{32} + \frac{80 x^{2}}{32} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Schritt 1.3.5.2

Vereinfache die linke Seite.

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Schritt 1.3.5.2.1

Kürze den gemeinsamen Faktor von $32$ .

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Schritt 1.3.5.2.1.1

Kürze den gemeinsamen Faktor.

$\frac{32 y}{32} = \frac{32}{32} + \frac{80 x}{32} + \frac{80 x^{2}}{32} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Schritt 1.3.5.2.1.2

Dividiere $y$ durch $1$ .

$y = \frac{32}{32} + \frac{80 x}{32} + \frac{80 x^{2}}{32} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Schritt 1.3.5.3

Vereinfache die rechte Seite.

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Schritt 1.3.5.3.1

Vereinfache jeden Term.

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Schritt 1.3.5.3.1.1

Dividiere $32$ durch $32$ .

$y = 1 + \frac{80 x}{32} + \frac{80 x^{2}}{32} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Schritt 1.3.5.3.1.2

Kürze den gemeinsamen Teiler von $80$ und $32$ .

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Schritt 1.3.5.3.1.2.1

Faktorisiere $16$ aus $80 x$ heraus.

$y = 1 + \frac{16 (5 x)}{32} + \frac{80 x^{2}}{32} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Schritt 1.3.5.3.1.2.2

Kürze die gemeinsamen Faktoren.

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Schritt 1.3.5.3.1.2.2.1

Faktorisiere $16$ aus $32$ heraus.

$y = 1 + \frac{16 (5 x)}{16 (2)} + \frac{80 x^{2}}{32} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Schritt 1.3.5.3.1.2.2.2

Kürze den gemeinsamen Faktor.

$y = 1 + \frac{16 (5 x)}{16 \cdot 2} + \frac{80 x^{2}}{32} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Schritt 1.3.5.3.1.2.2.3

Forme den Ausdruck um.

$y = 1 + \frac{5 x}{2} + \frac{80 x^{2}}{32} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Schritt 1.3.5.3.1.3

Kürze den gemeinsamen Teiler von $80$ und $32$ .

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Schritt 1.3.5.3.1.3.1

Faktorisiere $16$ aus $80 x^{2}$ heraus.

$y = 1 + \frac{5 x}{2} + \frac{16 (5 x^{2})}{32} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Schritt 1.3.5.3.1.3.2

Kürze die gemeinsamen Faktoren.

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Schritt 1.3.5.3.1.3.2.1

Faktorisiere $16$ aus $32$ heraus.

$y = 1 + \frac{5 x}{2} + \frac{16 (5 x^{2})}{16 (2)} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Schritt 1.3.5.3.1.3.2.2

Kürze den gemeinsamen Faktor.

$y = 1 + \frac{5 x}{2} + \frac{16 (5 x^{2})}{16 \cdot 2} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Schritt 1.3.5.3.1.3.2.3

Forme den Ausdruck um.

$y = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{40 x^{3}}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Schritt 1.3.5.3.1.4

Kürze den gemeinsamen Teiler von $40$ und $32$ .

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Schritt 1.3.5.3.1.4.1

Faktorisiere $8$ aus $40 x^{3}$ heraus.

$y = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{8 (5 x^{3})}{32} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Schritt 1.3.5.3.1.4.2

Kürze die gemeinsamen Faktoren.

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Schritt 1.3.5.3.1.4.2.1

Faktorisiere $8$ aus $32$ heraus.

$y = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{8 (5 x^{3})}{8 (4)} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Schritt 1.3.5.3.1.4.2.2

Kürze den gemeinsamen Faktor.

$y = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{8 (5 x^{3})}{8 \cdot 4} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Schritt 1.3.5.3.1.4.2.3

Forme den Ausdruck um.

$y = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{10 x^{4}}{32} + \frac{x^{5}}{32}$

Schritt 1.3.5.3.1.5

Kürze den gemeinsamen Teiler von $10$ und $32$ .

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Schritt 1.3.5.3.1.5.1

Faktorisiere $2$ aus $10 x^{4}$ heraus.

$y = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{2 (5 x^{4})}{32} + \frac{x^{5}}{32}$

Schritt 1.3.5.3.1.5.2

Kürze die gemeinsamen Faktoren.

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Schritt 1.3.5.3.1.5.2.1

Faktorisiere $2$ aus $32$ heraus.

$y = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{2 (5 x^{4})}{2 (16)} + \frac{x^{5}}{32}$

Schritt 1.3.5.3.1.5.2.2

Kürze den gemeinsamen Faktor.

$y = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{2 (5 x^{4})}{2 \cdot 16} + \frac{x^{5}}{32}$

Schritt 1.3.5.3.1.5.2.3

Forme den Ausdruck um.

$y = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}$

Schritt 1.4

Ersetze $y$ durch $f^{- 1} (x)$ , um die endgültige Lösung anzuzeigen.

$f^{- 1} (x) = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}$

Schritt 1.5

Überprüfe, ob $f^{- 1} (x) = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}$ die Umkehrfunktion von $f (x) = 2 x^{\frac{1}{5}} - 2$ ist.

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Schritt 1.5.1

Um die inverse Funktion (Umkehrfunktion) zu prüfen, prüfe ob $f^{- 1} (f (x)) = x$ ist und $f (f^{- 1} (x)) = x$ ist.

Schritt 1.5.2

Berechne $f^{- 1} (f (x))$ .

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Schritt 1.5.2.1

Bilde die verkettete Ergebnisfunktion.

$f^{- 1} (f (x))$

Schritt 1.5.2.2

Berechne $f^{- 1} (2 x^{\frac{1}{5}} - 2)$ durch Einsetzen des Wertes von $f$ in $f^{- 1}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + \frac{5 (2 x^{\frac{1}{5}} - 2)}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3

Vereinfache jeden Term.

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Schritt 1.5.2.3.1

Faktorisiere $2$ aus $5 (2 x^{\frac{1}{5}} - 2)$ heraus.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + \frac{2 (5 (x^{\frac{1}{5}} - 1))}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.2

Kürze die gemeinsamen Faktoren.

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Schritt 1.5.2.3.2.1

Faktorisiere $2$ aus $2$ heraus.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + \frac{2 (5 (x^{\frac{1}{5}} - 1))}{2 (1)} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.2.2

Kürze den gemeinsamen Faktor.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + \frac{2 (5 (x^{\frac{1}{5}} - 1))}{2 \cdot 1} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.2.3

Forme den Ausdruck um.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + \frac{5 (x^{\frac{1}{5}} - 1)}{1} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.2.4

Dividiere $5 (x^{\frac{1}{5}} - 1)$ durch $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 (x^{\frac{1}{5}} - 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.3

Wende das Distributivgesetz an.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} + 5 \cdot - 1 + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.4

Mutltipliziere $5$ mit $- 1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.5

Vereinfache den Zähler.

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Schritt 1.5.2.3.5.1

Faktorisiere $2$ aus $2 x^{\frac{1}{5}} - 2$ heraus.

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Schritt 1.5.2.3.5.1.1

Faktorisiere $2$ aus $2 x^{\frac{1}{5}}$ heraus.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{5 {(2 (x^{\frac{1}{5}}) - 2)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.5.1.2

Faktorisiere $2$ aus $- 2$ heraus.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{5 {(2 (x^{\frac{1}{5}}) + 2 (- 1))}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.5.1.3

Faktorisiere $2$ aus $2 (x^{\frac{1}{5}}) + 2 (- 1)$ heraus.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{5 {(2 (x^{\frac{1}{5}} - 1))}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.5.2

Wende die Produktregel auf $2 (x^{\frac{1}{5}} - 1)$ an.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{5 \cdot (2^{2} {(x^{\frac{1}{5}} - 1)}^{2})}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.5.3

Potenziere $2$ mit $2$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{5 \cdot (4 {(x^{\frac{1}{5}} - 1)}^{2})}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.5.4

Mutltipliziere $5$ mit $4$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{20 {(x^{\frac{1}{5}} - 1)}^{2}}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.6

Faktorisiere $2$ aus $20 {(x^{\frac{1}{5}} - 1)}^{2}$ heraus.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{2 (10 {(x^{\frac{1}{5}} - 1)}^{2})}{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.7

Kürze die gemeinsamen Faktoren.

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Schritt 1.5.2.3.7.1

Faktorisiere $2$ aus $2$ heraus.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{2 (10 {(x^{\frac{1}{5}} - 1)}^{2})}{2 (1)} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.7.2

Kürze den gemeinsamen Faktor.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{2 (10 {(x^{\frac{1}{5}} - 1)}^{2})}{2 \cdot 1} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.7.3

Forme den Ausdruck um.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + \frac{10 {(x^{\frac{1}{5}} - 1)}^{2}}{1} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.7.4

Dividiere $10 {(x^{\frac{1}{5}} - 1)}^{2}$ durch $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 {(x^{\frac{1}{5}} - 1)}^{2} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.8

Schreibe ${(x^{\frac{1}{5}} - 1)}^{2}$ als $(x^{\frac{1}{5}} - 1) (x^{\frac{1}{5}} - 1)$ um.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 ((x^{\frac{1}{5}} - 1) (x^{\frac{1}{5}} - 1)) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.9

Multipliziere $(x^{\frac{1}{5}} - 1) (x^{\frac{1}{5}} - 1)$ aus unter Verwendung der FOIL-Methode.

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Schritt 1.5.2.3.9.1

Wende das Distributivgesetz an.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{1}{5}} (x^{\frac{1}{5}} - 1) - 1 (x^{\frac{1}{5}} - 1)) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.9.2

Wende das Distributivgesetz an.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{1}{5}} x^{\frac{1}{5}} + x^{\frac{1}{5}} \cdot - 1 - 1 (x^{\frac{1}{5}} - 1)) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.9.3

Wende das Distributivgesetz an.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{1}{5}} x^{\frac{1}{5}} + x^{\frac{1}{5}} \cdot - 1 - 1 x^{\frac{1}{5}} - 1 \cdot - 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.10

Vereinfache und fasse gleichartige Terme zusammen.

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Schritt 1.5.2.3.10.1

Vereinfache jeden Term.

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Schritt 1.5.2.3.10.1.1

Multipliziere $x^{\frac{1}{5}}$ mit $x^{\frac{1}{5}}$ durch Addieren der Exponenten.

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Schritt 1.5.2.3.10.1.1.1

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{1}{5} + \frac{1}{5}} + x^{\frac{1}{5}} \cdot - 1 - 1 x^{\frac{1}{5}} - 1 \cdot - 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.10.1.1.2

Vereinige die Zähler über dem gemeinsamen Nenner.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{1 + 1}{5}} + x^{\frac{1}{5}} \cdot - 1 - 1 x^{\frac{1}{5}} - 1 \cdot - 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.10.1.1.3

Addiere $1$ und $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{2}{5}} + x^{\frac{1}{5}} \cdot - 1 - 1 x^{\frac{1}{5}} - 1 \cdot - 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.10.1.2

Bringe $- 1$ auf die linke Seite von $x^{\frac{1}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{2}{5}} - 1 \cdot x^{\frac{1}{5}} - 1 x^{\frac{1}{5}} - 1 \cdot - 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.10.1.3

Schreibe $- 1 x^{\frac{1}{5}}$ als $- x^{\frac{1}{5}}$ um.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{2}{5}} - x^{\frac{1}{5}} - 1 x^{\frac{1}{5}} - 1 \cdot - 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.10.1.4

Schreibe $- 1 x^{\frac{1}{5}}$ als $- x^{\frac{1}{5}}$ um.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{2}{5}} - x^{\frac{1}{5}} - x^{\frac{1}{5}} - 1 \cdot - 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.10.1.5

Mutltipliziere $- 1$ mit $- 1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{2}{5}} - x^{\frac{1}{5}} - x^{\frac{1}{5}} + 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.10.2

Subtrahiere $x^{\frac{1}{5}}$ von $- x^{\frac{1}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 (x^{\frac{2}{5}} - 2 x^{\frac{1}{5}} + 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.11

Wende das Distributivgesetz an.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} + 10 (- 2 x^{\frac{1}{5}}) + 10 \cdot 1 + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.12

Vereinfache.

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Schritt 1.5.2.3.12.1

Mutltipliziere $- 2$ mit $10$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 \cdot 1 + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.12.2

Mutltipliziere $10$ mit $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.13

Vereinfache den Zähler.

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Schritt 1.5.2.3.13.1

Faktorisiere $2$ aus $2 x^{\frac{1}{5}} - 2$ heraus.

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Schritt 1.5.2.3.13.1.1

Faktorisiere $2$ aus $2 x^{\frac{1}{5}}$ heraus.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{5 {(2 (x^{\frac{1}{5}}) - 2)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.13.1.2

Faktorisiere $2$ aus $- 2$ heraus.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{5 {(2 (x^{\frac{1}{5}}) + 2 (- 1))}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.13.1.3

Faktorisiere $2$ aus $2 (x^{\frac{1}{5}}) + 2 (- 1)$ heraus.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{5 {(2 (x^{\frac{1}{5}} - 1))}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.13.2

Wende die Produktregel auf $2 (x^{\frac{1}{5}} - 1)$ an.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{5 \cdot (2^{3} {(x^{\frac{1}{5}} - 1)}^{3})}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.13.3

Potenziere $2$ mit $3$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{5 \cdot (8 {(x^{\frac{1}{5}} - 1)}^{3})}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.13.4

Mutltipliziere $5$ mit $8$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{40 {(x^{\frac{1}{5}} - 1)}^{3}}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.14

Faktorisiere $4$ aus $40 {(x^{\frac{1}{5}} - 1)}^{3}$ heraus.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{4 (10 {(x^{\frac{1}{5}} - 1)}^{3})}{4} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.15

Kürze die gemeinsamen Faktoren.

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Schritt 1.5.2.3.15.1

Faktorisiere $4$ aus $4$ heraus.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{4 (10 {(x^{\frac{1}{5}} - 1)}^{3})}{4 (1)} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.15.2

Kürze den gemeinsamen Faktor.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{4 (10 {(x^{\frac{1}{5}} - 1)}^{3})}{4 \cdot 1} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.15.3

Forme den Ausdruck um.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + \frac{10 {(x^{\frac{1}{5}} - 1)}^{3}}{1} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.15.4

Dividiere $10 {(x^{\frac{1}{5}} - 1)}^{3}$ durch $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 {(x^{\frac{1}{5}} - 1)}^{3} + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.16

Wende den binomischen Lehrsatz an.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 ({(x^{\frac{1}{5}})}^{3} + 3 {(x^{\frac{1}{5}})}^{2} \cdot - 1 + 3 x^{\frac{1}{5}} {(- 1)}^{2} + {(- 1)}^{3}) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.17

Vereinfache jeden Term.

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Schritt 1.5.2.3.17.1

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{3}$ .

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Schritt 1.5.2.3.17.1.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 (x^{\frac{1}{5} \cdot 3} + 3 {(x^{\frac{1}{5}})}^{2} \cdot - 1 + 3 x^{\frac{1}{5}} {(- 1)}^{2} + {(- 1)}^{3}) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.17.1.2

Kombiniere $\frac{1}{5}$ und $3$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 (x^{\frac{3}{5}} + 3 {(x^{\frac{1}{5}})}^{2} \cdot - 1 + 3 x^{\frac{1}{5}} {(- 1)}^{2} + {(- 1)}^{3}) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.17.2

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{2}$ .

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Schritt 1.5.2.3.17.2.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 (x^{\frac{3}{5}} + 3 x^{\frac{1}{5} \cdot 2} \cdot - 1 + 3 x^{\frac{1}{5}} {(- 1)}^{2} + {(- 1)}^{3}) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.17.2.2

Kombiniere $\frac{1}{5}$ und $2$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 (x^{\frac{3}{5}} + 3 x^{\frac{2}{5}} \cdot - 1 + 3 x^{\frac{1}{5}} {(- 1)}^{2} + {(- 1)}^{3}) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.17.3

Mutltipliziere $- 1$ mit $3$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 (x^{\frac{3}{5}} - 3 x^{\frac{2}{5}} + 3 x^{\frac{1}{5}} {(- 1)}^{2} + {(- 1)}^{3}) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.17.4

Potenziere $- 1$ mit $2$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 (x^{\frac{3}{5}} - 3 x^{\frac{2}{5}} + 3 x^{\frac{1}{5}} \cdot 1 + {(- 1)}^{3}) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.17.5

Mutltipliziere $3$ mit $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 (x^{\frac{3}{5}} - 3 x^{\frac{2}{5}} + 3 x^{\frac{1}{5}} + {(- 1)}^{3}) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.17.6

Potenziere $- 1$ mit $3$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 (x^{\frac{3}{5}} - 3 x^{\frac{2}{5}} + 3 x^{\frac{1}{5}} - 1) + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.18

Wende das Distributivgesetz an.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} + 10 (- 3 x^{\frac{2}{5}}) + 10 (3 x^{\frac{1}{5}}) + 10 \cdot - 1 + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.19

Vereinfache.

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Schritt 1.5.2.3.19.1

Mutltipliziere $- 3$ mit $10$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 10 (3 x^{\frac{1}{5}}) + 10 \cdot - 1 + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.19.2

Mutltipliziere $3$ mit $10$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} + 10 \cdot - 1 + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.19.3

Mutltipliziere $10$ mit $- 1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{5 {(2 x^{\frac{1}{5}} - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.20

Vereinfache den Zähler.

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Schritt 1.5.2.3.20.1

Faktorisiere $2$ aus $2 x^{\frac{1}{5}} - 2$ heraus.

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Schritt 1.5.2.3.20.1.1

Faktorisiere $2$ aus $2 x^{\frac{1}{5}}$ heraus.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{5 {(2 (x^{\frac{1}{5}}) - 2)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.20.1.2

Faktorisiere $2$ aus $- 2$ heraus.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{5 {(2 (x^{\frac{1}{5}}) + 2 (- 1))}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.20.1.3

Faktorisiere $2$ aus $2 (x^{\frac{1}{5}}) + 2 (- 1)$ heraus.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{5 {(2 (x^{\frac{1}{5}} - 1))}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.20.2

Wende die Produktregel auf $2 (x^{\frac{1}{5}} - 1)$ an.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{5 \cdot (2^{4} {(x^{\frac{1}{5}} - 1)}^{4})}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.20.3

Potenziere $2$ mit $4$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{5 \cdot (16 {(x^{\frac{1}{5}} - 1)}^{4})}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.20.4

Mutltipliziere $5$ mit $16$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{80 {(x^{\frac{1}{5}} - 1)}^{4}}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.21

Faktorisiere $16$ aus $80 {(x^{\frac{1}{5}} - 1)}^{4}$ heraus.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{16 (5 {(x^{\frac{1}{5}} - 1)}^{4})}{16} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.22

Kürze die gemeinsamen Faktoren.

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Schritt 1.5.2.3.22.1

Faktorisiere $16$ aus $16$ heraus.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{16 (5 {(x^{\frac{1}{5}} - 1)}^{4})}{16 (1)} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.22.2

Kürze den gemeinsamen Faktor.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{16 (5 {(x^{\frac{1}{5}} - 1)}^{4})}{16 \cdot 1} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.22.3

Forme den Ausdruck um.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + \frac{5 {(x^{\frac{1}{5}} - 1)}^{4}}{1} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.22.4

Dividiere $5 {(x^{\frac{1}{5}} - 1)}^{4}$ durch $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 {(x^{\frac{1}{5}} - 1)}^{4} + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.23

Wende den binomischen Lehrsatz an.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 ({(x^{\frac{1}{5}})}^{4} + 4 {(x^{\frac{1}{5}})}^{3} \cdot - 1 + 6 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.24

Vereinfache jeden Term.

Tippen, um mehr Schritte zu sehen ...

Schritt 1.5.2.3.24.1

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{4}$ .

Tippen, um mehr Schritte zu sehen ...

Schritt 1.5.2.3.24.1.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{1}{5} \cdot 4} + 4 {(x^{\frac{1}{5}})}^{3} \cdot - 1 + 6 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.24.1.2

Kombiniere $\frac{1}{5}$ und $4$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} + 4 {(x^{\frac{1}{5}})}^{3} \cdot - 1 + 6 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.24.2

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{3}$ .

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Schritt 1.5.2.3.24.2.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} + 4 x^{\frac{1}{5} \cdot 3} \cdot - 1 + 6 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.24.2.2

Kombiniere $\frac{1}{5}$ und $3$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} + 4 x^{\frac{3}{5}} \cdot - 1 + 6 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.24.3

Mutltipliziere $- 1$ mit $4$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} - 4 x^{\frac{3}{5}} + 6 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.24.4

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{2}$ .

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Schritt 1.5.2.3.24.4.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} - 4 x^{\frac{3}{5}} + 6 x^{\frac{1}{5} \cdot 2} {(- 1)}^{2} + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.24.4.2

Kombiniere $\frac{1}{5}$ und $2$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} - 4 x^{\frac{3}{5}} + 6 x^{\frac{2}{5}} {(- 1)}^{2} + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.24.5

Potenziere $- 1$ mit $2$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} - 4 x^{\frac{3}{5}} + 6 x^{\frac{2}{5}} \cdot 1 + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.24.6

Mutltipliziere $6$ mit $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} - 4 x^{\frac{3}{5}} + 6 x^{\frac{2}{5}} + 4 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.24.7

Potenziere $- 1$ mit $3$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} - 4 x^{\frac{3}{5}} + 6 x^{\frac{2}{5}} + 4 x^{\frac{1}{5}} \cdot - 1 + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.24.8

Mutltipliziere $- 1$ mit $4$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} - 4 x^{\frac{3}{5}} + 6 x^{\frac{2}{5}} - 4 x^{\frac{1}{5}} + {(- 1)}^{4}) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.24.9

Potenziere $- 1$ mit $4$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 (x^{\frac{4}{5}} - 4 x^{\frac{3}{5}} + 6 x^{\frac{2}{5}} - 4 x^{\frac{1}{5}} + 1) + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.25

Wende das Distributivgesetz an.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} + 5 (- 4 x^{\frac{3}{5}}) + 5 (6 x^{\frac{2}{5}}) + 5 (- 4 x^{\frac{1}{5}}) + 5 \cdot 1 + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.26

Vereinfache.

Tippen, um mehr Schritte zu sehen ...

Schritt 1.5.2.3.26.1

Mutltipliziere $- 4$ mit $5$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 5 (6 x^{\frac{2}{5}}) + 5 (- 4 x^{\frac{1}{5}}) + 5 \cdot 1 + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.26.2

Mutltipliziere $6$ mit $5$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} + 5 (- 4 x^{\frac{1}{5}}) + 5 \cdot 1 + \frac{{(2 x^{\frac{1}{5}} - 2)}^{5}}{32}$

Schritt 1.5.2.3.26.3

Mutltipliziere $- 4$ mit $5$ .

Schritt 1.5.2.3.26.4

Mutltipliziere $5$ mit $1$ .

Schritt 1.5.2.3.27

Vereinfache den Zähler.

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Schritt 1.5.2.3.27.1

Faktorisiere $2$ aus $2 x^{\frac{1}{5}} - 2$ heraus.

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Schritt 1.5.2.3.27.1.1

Faktorisiere $2$ aus $2 x^{\frac{1}{5}}$ heraus.

Schritt 1.5.2.3.27.1.2

Faktorisiere $2$ aus $- 2$ heraus.

Schritt 1.5.2.3.27.1.3

Faktorisiere $2$ aus $2 (x^{\frac{1}{5}}) + 2 (- 1)$ heraus.

Schritt 1.5.2.3.27.2

Wende die Produktregel auf $2 (x^{\frac{1}{5}} - 1)$ an.

Schritt 1.5.2.3.27.3

Potenziere $2$ mit $5$ .

Schritt 1.5.2.3.28

Kürze den gemeinsamen Faktor.

Schritt 1.5.2.3.29

Dividiere ${(x^{\frac{1}{5}} - 1)}^{5}$ durch $1$ .

Schritt 1.5.2.3.30

Wende den binomischen Lehrsatz an.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + {(x^{\frac{1}{5}})}^{5} + 5 {(x^{\frac{1}{5}})}^{4} \cdot - 1 + 10 {(x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Schritt 1.5.2.3.31

Vereinfache jeden Term.

Tippen, um mehr Schritte zu sehen ...

Schritt 1.5.2.3.31.1

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{5}$ .

Tippen, um mehr Schritte zu sehen ...

Schritt 1.5.2.3.31.1.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x^{\frac{1}{5} \cdot 5} + 5 {(x^{\frac{1}{5}})}^{4} \cdot - 1 + 10 {(x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Schritt 1.5.2.3.31.1.2

Kürze den gemeinsamen Faktor von $5$ .

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Schritt 1.5.2.3.31.1.2.1

Kürze den gemeinsamen Faktor.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x^{\frac{1}{5} \cdot 5} + 5 {(x^{\frac{1}{5}})}^{4} \cdot - 1 + 10 {(x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Schritt 1.5.2.3.31.1.2.2

Forme den Ausdruck um.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x + 5 {(x^{\frac{1}{5}})}^{4} \cdot - 1 + 10 {(x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Schritt 1.5.2.3.31.2

Vereinfache.

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x + 5 {(x^{\frac{1}{5}})}^{4} \cdot - 1 + 10 {(x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Schritt 1.5.2.3.31.3

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{4}$ .

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Schritt 1.5.2.3.31.3.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x + 5 x^{\frac{1}{5} \cdot 4} \cdot - 1 + 10 {(x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Schritt 1.5.2.3.31.3.2

Kombiniere $\frac{1}{5}$ und $4$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x + 5 x^{\frac{4}{5}} \cdot - 1 + 10 {(x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Schritt 1.5.2.3.31.4

Mutltipliziere $- 1$ mit $5$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 {(x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Schritt 1.5.2.3.31.5

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{3}$ .

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Schritt 1.5.2.3.31.5.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{1}{5} \cdot 3} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Schritt 1.5.2.3.31.5.2

Kombiniere $\frac{1}{5}$ und $3$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} {(- 1)}^{2} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Schritt 1.5.2.3.31.6

Potenziere $- 1$ mit $2$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} \cdot 1 + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Schritt 1.5.2.3.31.7

Mutltipliziere $10$ mit $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} + 10 {(x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Schritt 1.5.2.3.31.8

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{2}$ .

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Schritt 1.5.2.3.31.8.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} + 10 x^{\frac{1}{5} \cdot 2} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Schritt 1.5.2.3.31.8.2

Kombiniere $\frac{1}{5}$ und $2$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} + 10 x^{\frac{2}{5}} {(- 1)}^{3} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Schritt 1.5.2.3.31.9

Potenziere $- 1$ mit $3$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} + 10 x^{\frac{2}{5}} \cdot - 1 + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Schritt 1.5.2.3.31.10

Mutltipliziere $- 1$ mit $10$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}$

Schritt 1.5.2.3.31.11

Potenziere $- 1$ mit $4$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} \cdot 1 + {(- 1)}^{5}$

Schritt 1.5.2.3.31.12

Mutltipliziere $5$ mit $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} + {(- 1)}^{5}$

Schritt 1.5.2.3.31.13

Potenziere $- 1$ mit $5$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$

Schritt 1.5.2.4

Vereinfache durch Addieren von Termen.

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Schritt 1.5.2.4.1

Vereine die Terme mit entgegengesetztem Vorzeichen in $1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 10 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$ .

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Schritt 1.5.2.4.1.1

Subtrahiere $10$ von $10$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} + 0 + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$

Schritt 1.5.2.4.1.2

Addiere $1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}}$ und $0$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} - 30 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 30 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$

Schritt 1.5.2.4.1.3

Addiere $- 30 x^{\frac{2}{5}}$ und $30 x^{\frac{2}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} + 0 - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$

Schritt 1.5.2.4.1.4

Addiere $1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}}$ und $0$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 5 + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + 5 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$

Schritt 1.5.2.4.1.5

Addiere $- 5$ und $5$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + 0 + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$

Schritt 1.5.2.4.1.6

Addiere $1 + 5 x^{\frac{1}{5}} + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}}$ und $0$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} + 5 x^{\frac{4}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x - 5 x^{\frac{4}{5}} + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$

Schritt 1.5.2.4.1.7

Subtrahiere $5 x^{\frac{4}{5}}$ von $5 x^{\frac{4}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x + 0 + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$

Schritt 1.5.2.4.1.8

Addiere $1 + 5 x^{\frac{1}{5}} + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x$ und $0$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} + 10 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x + 10 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} - 1$

Schritt 1.5.2.4.1.9

Subtrahiere $10 x^{\frac{2}{5}}$ von $10 x^{\frac{2}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 1 + 5 x^{\frac{1}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x + 10 x^{\frac{3}{5}} + 0 + 5 x^{\frac{1}{5}} - 1$

Schritt 1.5.2.4.1.10

Addiere $1 + 5 x^{\frac{1}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x + 10 x^{\frac{3}{5}}$ und $0$ .

Schritt 1.5.2.4.1.11

Subtrahiere $1$ von $1$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 5 x^{\frac{1}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x + 10 x^{\frac{3}{5}} + 5 x^{\frac{1}{5}} + 0$

Schritt 1.5.2.4.1.12

Addiere $5 x^{\frac{1}{5}} - 20 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x + 10 x^{\frac{3}{5}} + 5 x^{\frac{1}{5}}$ und $0$ .

Schritt 1.5.2.4.2

Subtrahiere $20 x^{\frac{1}{5}}$ von $5 x^{\frac{1}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = - 15 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x + 10 x^{\frac{3}{5}} + 5 x^{\frac{1}{5}}$

Schritt 1.5.2.4.3

Addiere $- 15 x^{\frac{1}{5}}$ und $30 x^{\frac{1}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 15 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} - 20 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + x + 10 x^{\frac{3}{5}} + 5 x^{\frac{1}{5}}$

Schritt 1.5.2.4.4

Subtrahiere $20 x^{\frac{1}{5}}$ von $15 x^{\frac{1}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = - 5 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} - 20 x^{\frac{3}{5}} + x + 10 x^{\frac{3}{5}} + 5 x^{\frac{1}{5}}$

Schritt 1.5.2.4.5

Vereine die Terme mit entgegengesetztem Vorzeichen in $- 5 x^{\frac{1}{5}} + 10 x^{\frac{3}{5}} - 20 x^{\frac{3}{5}} + x + 10 x^{\frac{3}{5}} + 5 x^{\frac{1}{5}}$ .

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Schritt 1.5.2.4.5.1

Addiere $- 5 x^{\frac{1}{5}}$ und $5 x^{\frac{1}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 10 x^{\frac{3}{5}} - 20 x^{\frac{3}{5}} + x + 10 x^{\frac{3}{5}} + 0$

Schritt 1.5.2.4.5.2

Addiere $10 x^{\frac{3}{5}} - 20 x^{\frac{3}{5}} + x + 10 x^{\frac{3}{5}}$ und $0$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = 10 x^{\frac{3}{5}} - 20 x^{\frac{3}{5}} + x + 10 x^{\frac{3}{5}}$

Schritt 1.5.2.4.6

Subtrahiere $20 x^{\frac{3}{5}}$ von $10 x^{\frac{3}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = - 10 x^{\frac{3}{5}} + x + 10 x^{\frac{3}{5}}$

Schritt 1.5.2.4.7

Vereine die Terme mit entgegengesetztem Vorzeichen in $- 10 x^{\frac{3}{5}} + x + 10 x^{\frac{3}{5}}$ .

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Schritt 1.5.2.4.7.1

Addiere $- 10 x^{\frac{3}{5}}$ und $10 x^{\frac{3}{5}}$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = x + 0$

Schritt 1.5.2.4.7.2

Addiere $x$ und $0$ .

$f^{- 1} (2 x^{\frac{1}{5}} - 2) = x$

Schritt 1.5.3

Berechne $f (f^{- 1} (x))$ .

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Schritt 1.5.3.1

Bilde die verkettete Ergebnisfunktion.

$f (f^{- 1} (x))$

Schritt 1.5.3.2

Berechne $f (1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32})$ durch Einsetzen des Wertes von $f^{- 1}$ in $f$ .

$f (1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}) = 2 {(1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32})}^{\frac{1}{5}} - 2$

Schritt 1.5.3.3

Bewege $1$ .

$f (1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}) = 2 {(\frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32} + 1)}^{\frac{1}{5}} - 2$

Schritt 1.5.3.4

Bewege $\frac{5 x}{2}$ .

$f (1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}) = 2 {(\frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32} + \frac{5 x}{2} + 1)}^{\frac{1}{5}} - 2$

Schritt 1.5.3.5

Bewege $\frac{5 x^{2}}{2}$ .

$f (1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}) = 2 {(\frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32} + \frac{5 x^{2}}{2} + \frac{5 x}{2} + 1)}^{\frac{1}{5}} - 2$

Schritt 1.5.3.6

Bewege $\frac{5 x^{3}}{4}$ .

$f (1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}) = 2 {(\frac{5 x^{4}}{16} + \frac{x^{5}}{32} + \frac{5 x^{3}}{4} + \frac{5 x^{2}}{2} + \frac{5 x}{2} + 1)}^{\frac{1}{5}} - 2$

Schritt 1.5.3.7

Stelle $\frac{5 x^{4}}{16}$ und $\frac{x^{5}}{32}$ um.

$f (1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}) = 2 {(\frac{x^{5}}{32} + \frac{5 x^{4}}{16} + \frac{5 x^{3}}{4} + \frac{5 x^{2}}{2} + \frac{5 x}{2} + 1)}^{\frac{1}{5}} - 2$

Schritt 1.5.4

Da $f^{- 1} (f (x)) = x$ und $f (f^{- 1} (x)) = x$ gleich sind, ist $f^{- 1} (x) = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}$ die inverse Funktion (Umkehrfunktion) von $f (x) = 2 x^{\frac{1}{5}} - 2$ .

$f^{- 1} (x) = 1 + \frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32}$

Schritt 2

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Schritt 2.1

Bewege $1$ .

$\frac{5 x}{2} + \frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32} + 1$

Schritt 2.2

Bewege $\frac{5 x}{2}$ .

$\frac{5 x^{2}}{2} + \frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32} + \frac{5 x}{2} + 1$

Schritt 2.3

Bewege $\frac{5 x^{2}}{2}$ .

$\frac{5 x^{3}}{4} + \frac{5 x^{4}}{16} + \frac{x^{5}}{32} + \frac{5 x^{2}}{2} + \frac{5 x}{2} + 1$

Schritt 2.4

Bewege $\frac{5 x^{3}}{4}$ .

$\frac{5 x^{4}}{16} + \frac{x^{5}}{32} + \frac{5 x^{3}}{4} + \frac{5 x^{2}}{2} + \frac{5 x}{2} + 1$

Schritt 2.5

Stelle $\frac{5 x^{4}}{16}$ und $\frac{x^{5}}{32}$ um.

$\frac{x^{5}}{32} + \frac{5 x^{4}}{16} + \frac{5 x^{3}}{4} + \frac{5 x^{2}}{2} + \frac{5 x}{2} + 1$