Lineare Algebra Beispiele

차집합 b \ A 구하기 A=(1,3,5,6,7,9,11,12,13,15,17,18,19) , b=(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20)
A=(1,3,5,6,7,9,11,12,13,15,17,18,19)A=(1,3,5,6,7,9,11,12,13,15,17,18,19) , b=(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20)b=(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20)
Schritt 1
Gib die Darstellung der Schnittmenge der Mengen {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20}{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20} und {1,3,5,6,7,9,11,12,13,15,17,18,19}{1,3,5,6,7,9,11,12,13,15,17,18,19} wieder.
{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20}{1,3,5,6,7,9,11,12,13,15,17,18,19}{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20}{1,3,5,6,7,9,11,12,13,15,17,18,19}
Schritt 2
Die Schnittmenge zweier Mengen ist die Menge aller Elemente, die in beiden Mengen enthalten ist.
{1,3,5,6,7,9,11,12,13,15,17,18,19}{1,3,5,6,7,9,11,12,13,15,17,18,19}
Schritt 3
Die Komplementärmenge der beiden Mengen sind die verbleibenden Elemente von {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20}{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20}, die keine Elemente der Schnittmenge der beiden Mengen sind.
{2,4,8,10,14,16,20}{2,4,8,10,14,16,20}
 [x2  12  π  xdx ]  x2  12  π  xdx