Analysis Beispiele

$y = \sqrt[5]{\frac{x}{x^{2} - 1}}$

Schritt 1

Bestimme die erste Ableitung.

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Schritt 1.1

Benutze $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ , um $\sqrt[5]{\frac{x}{x^{2} - 1}}$ als ${(\frac{x}{x^{2} - 1})}^{\frac{1}{5}}$ neu zu schreiben.

$\frac{d}{d x} [{(\frac{x}{x^{2} - 1})}^{\frac{1}{5}}]$

Schritt 1.2

Differenziere unter Anwendung der Kettenregel, die besagt, dass $\frac{d}{d x} [f (g (x))]$ ist $f' (g (x)) g' (x)$ , mit $f (x) = x^{\frac{1}{5}}$ und $g (x) = \frac{x}{x^{2} - 1}$ .

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Schritt 1.2.1

Um die Kettenregel anzuwenden, ersetze $u$ durch $\frac{x}{x^{2} - 1}$ .

$\frac{d}{d u} [u^{\frac{1}{5}}] \frac{d}{d x} [\frac{x}{x^{2} - 1}]$

Schritt 1.2.2

Differenziere unter Anwendung der Potenzregel, die besagt, dass $\frac{d}{d u} [u^{n}]$ gleich $n u^{n - 1}$ ist mit $n = \frac{1}{5}$ .

$\frac{1}{5} u^{\frac{1}{5} - 1} \frac{d}{d x} [\frac{x}{x^{2} - 1}]$

Schritt 1.2.3

Ersetze alle $u$ durch $\frac{x}{x^{2} - 1}$ .

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{\frac{1}{5} - 1} \frac{d}{d x} [\frac{x}{x^{2} - 1}]$

Schritt 1.3

Um $- 1$ als Bruch mit einem gemeinsamen Nenner zu schreiben, multipliziere mit $\frac{5}{5}$ .

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{\frac{1}{5} - 1 \cdot \frac{5}{5}} \frac{d}{d x} [\frac{x}{x^{2} - 1}]$

Schritt 1.4

Kombiniere $- 1$ und $\frac{5}{5}$ .

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{\frac{1}{5} + \frac{- 1 \cdot 5}{5}} \frac{d}{d x} [\frac{x}{x^{2} - 1}]$

Schritt 1.5

Vereinige die Zähler über dem gemeinsamen Nenner.

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{\frac{1 - 1 \cdot 5}{5}} \frac{d}{d x} [\frac{x}{x^{2} - 1}]$

Schritt 1.6

Vereinfache den Zähler.

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Schritt 1.6.1

Mutltipliziere $- 1$ mit $5$ .

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{\frac{1 - 5}{5}} \frac{d}{d x} [\frac{x}{x^{2} - 1}]$

Schritt 1.6.2

Subtrahiere $5$ von $1$ .

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{\frac{- 4}{5}} \frac{d}{d x} [\frac{x}{x^{2} - 1}]$

Schritt 1.7

Ziehe das Minuszeichen vor den Bruch.

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{- \frac{4}{5}} \frac{d}{d x} [\frac{x}{x^{2} - 1}]$

Schritt 1.8

Differenziere unter Anwendung der Quotientenregel, die besagt, dass $\frac{d}{d x} [\frac{f (x)}{g (x)}]$ gleich $\frac{g (x) \frac{d}{d x} [f (x)] - f (x) \frac{d}{d x} [g (x)]}{{g (x)}^{2}}$ ist mit $f (x) = x$ und $g (x) = x^{2} - 1$ .

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{- \frac{4}{5}} \frac{(x^{2} - 1) \frac{d}{d x} [x] - x \frac{d}{d x} [x^{2} - 1]}{{(x^{2} - 1)}^{2}}$

Schritt 1.9

Differenziere.

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Schritt 1.9.1

Differenziere unter Anwendung der Potenzregel, die besagt, dass $\frac{d}{d x} [x^{n}]$ gleich $n x^{n - 1}$ ist mit $n = 1$ .

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{- \frac{4}{5}} \frac{(x^{2} - 1) \cdot 1 - x \frac{d}{d x} [x^{2} - 1]}{{(x^{2} - 1)}^{2}}$

Schritt 1.9.2

Mutltipliziere $x^{2} - 1$ mit $1$ .

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{- \frac{4}{5}} \frac{x^{2} - 1 - x \frac{d}{d x} [x^{2} - 1]}{{(x^{2} - 1)}^{2}}$

Schritt 1.9.3

Gemäß der Summenregel ist die Ableitung von $x^{2} - 1$ nach $x$ $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 1]$ .

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{- \frac{4}{5}} \frac{x^{2} - 1 - x (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 1])}{{(x^{2} - 1)}^{2}}$

Schritt 1.9.4

Differenziere unter Anwendung der Potenzregel, die besagt, dass $\frac{d}{d x} [x^{n}]$ gleich $n x^{n - 1}$ ist mit $n = 2$ .

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{- \frac{4}{5}} \frac{x^{2} - 1 - x (2 x + \frac{d}{d x} [- 1])}{{(x^{2} - 1)}^{2}}$

Schritt 1.9.5

Da $- 1$ konstant bezüglich $x$ ist, ist die Ableitung von $- 1$ bezüglich $x$ gleich $0$ .

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{- \frac{4}{5}} \frac{x^{2} - 1 - x (2 x + 0)}{{(x^{2} - 1)}^{2}}$

Schritt 1.9.6

Vereinfache den Ausdruck.

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Schritt 1.9.6.1

Addiere $2 x$ und $0$ .

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{- \frac{4}{5}} \frac{x^{2} - 1 - x (2 x)}{{(x^{2} - 1)}^{2}}$

Schritt 1.9.6.2

Mutltipliziere $2$ mit $- 1$ .

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{- \frac{4}{5}} \frac{x^{2} - 1 - 2 x \cdot x}{{(x^{2} - 1)}^{2}}$

Schritt 1.10

Potenziere $x$ mit $1$ .

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{- \frac{4}{5}} \frac{x^{2} - 1 - 2 (x^{1} x)}{{(x^{2} - 1)}^{2}}$

Schritt 1.11

Potenziere $x$ mit $1$ .

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{- \frac{4}{5}} \frac{x^{2} - 1 - 2 (x^{1} x^{1})}{{(x^{2} - 1)}^{2}}$

Schritt 1.12

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{- \frac{4}{5}} \frac{x^{2} - 1 - 2 x^{1 + 1}}{{(x^{2} - 1)}^{2}}$

Schritt 1.13

Addiere $1$ und $1$ .

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{- \frac{4}{5}} \frac{x^{2} - 1 - 2 x^{2}}{{(x^{2} - 1)}^{2}}$

Schritt 1.14

Subtrahiere $2 x^{2}$ von $x^{2}$ .

$\frac{1}{5} {(\frac{x}{x^{2} - 1})}^{- \frac{4}{5}} \frac{- x^{2} - 1}{{(x^{2} - 1)}^{2}}$

Schritt 1.15

Mutltipliziere $\frac{- x^{2} - 1}{{(x^{2} - 1)}^{2}}$ mit $\frac{1}{5}$ .

$\frac{- x^{2} - 1}{{(x^{2} - 1)}^{2} \cdot 5} {(\frac{x}{x^{2} - 1})}^{- \frac{4}{5}}$

Schritt 1.16

Bringe $5$ auf die linke Seite von ${(x^{2} - 1)}^{2}$ .

$\frac{- x^{2} - 1}{5 \cdot {(x^{2} - 1)}^{2}} {(\frac{x}{x^{2} - 1})}^{- \frac{4}{5}}$

Schritt 1.17

Vereinfache.

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Schritt 1.17.1

Ändere das Vorzeichen des Exponenten durch Umschreiben der Basis als ihren Kehrwert.

$\frac{- x^{2} - 1}{5 {(x^{2} - 1)}^{2}} {(\frac{x^{2} - 1}{x})}^{\frac{4}{5}}$

Schritt 1.17.2

Wende die Produktregel auf $\frac{x^{2} - 1}{x}$ an.

$\frac{- x^{2} - 1}{5 {(x^{2} - 1)}^{2}} \cdot \frac{{(x^{2} - 1)}^{\frac{4}{5}}}{x^{\frac{4}{5}}}$

Schritt 1.17.3

Vereine die Terme

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Schritt 1.17.3.1

Mutltipliziere $\frac{- x^{2} - 1}{5 {(x^{2} - 1)}^{2}}$ mit $\frac{{(x^{2} - 1)}^{\frac{4}{5}}}{x^{\frac{4}{5}}}$ .

$\frac{(- x^{2} - 1) {(x^{2} - 1)}^{\frac{4}{5}}}{5 {(x^{2} - 1)}^{2} x^{\frac{4}{5}}}$

Schritt 1.17.3.2

Bringe ${(x^{2} - 1)}^{\frac{4}{5}}$ in den Nenner mit Hilfe der Regel des negativen Exponenten $b^{n} = \frac{1}{b^{- n}}$ .

$\frac{- x^{2} - 1}{5 {(x^{2} - 1)}^{2} x^{\frac{4}{5}} {(x^{2} - 1)}^{- \frac{4}{5}}}$

Schritt 1.17.3.3

Multipliziere ${(x^{2} - 1)}^{2}$ mit ${(x^{2} - 1)}^{- \frac{4}{5}}$ durch Addieren der Exponenten.

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Schritt 1.17.3.3.1

Bewege ${(x^{2} - 1)}^{- \frac{4}{5}}$ .

$\frac{- x^{2} - 1}{5 ({(x^{2} - 1)}^{- \frac{4}{5}} {(x^{2} - 1)}^{2}) x^{\frac{4}{5}}}$

Schritt 1.17.3.3.2

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$\frac{- x^{2} - 1}{5 {(x^{2} - 1)}^{- \frac{4}{5} + 2} x^{\frac{4}{5}}}$

Schritt 1.17.3.3.3

Um $2$ als Bruch mit einem gemeinsamen Nenner zu schreiben, multipliziere mit $\frac{5}{5}$ .

$\frac{- x^{2} - 1}{5 {(x^{2} - 1)}^{- \frac{4}{5} + 2 \cdot \frac{5}{5}} x^{\frac{4}{5}}}$

Schritt 1.17.3.3.4

Kombiniere $2$ und $\frac{5}{5}$ .

$\frac{- x^{2} - 1}{5 {(x^{2} - 1)}^{- \frac{4}{5} + \frac{2 \cdot 5}{5}} x^{\frac{4}{5}}}$

Schritt 1.17.3.3.5

Vereinige die Zähler über dem gemeinsamen Nenner.

$\frac{- x^{2} - 1}{5 {(x^{2} - 1)}^{\frac{- 4 + 2 \cdot 5}{5}} x^{\frac{4}{5}}}$

Schritt 1.17.3.3.6

Vereinfache den Zähler.

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Schritt 1.17.3.3.6.1

Mutltipliziere $2$ mit $5$ .

$\frac{- x^{2} - 1}{5 {(x^{2} - 1)}^{\frac{- 4 + 10}{5}} x^{\frac{4}{5}}}$

Schritt 1.17.3.3.6.2

Addiere $- 4$ und $10$ .

$\frac{- x^{2} - 1}{5 {(x^{2} - 1)}^{\frac{6}{5}} x^{\frac{4}{5}}}$

Schritt 1.17.4

Stelle die Terme um.

$\frac{- x^{2} - 1}{5 x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}}$

Schritt 1.17.5

Faktorisiere $- 1$ aus $- x^{2}$ heraus.

$\frac{- (x^{2}) - 1}{5 x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}}$

Schritt 1.17.6

Schreibe $- 1$ als $- 1 (1)$ um.

$\frac{- (x^{2}) - 1 (1)}{5 x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}}$

Schritt 1.17.7

Faktorisiere $- 1$ aus $- (x^{2}) - 1 (1)$ heraus.

$\frac{- (x^{2} + 1)}{5 x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}}$

Schritt 1.17.8

Schreibe $- (x^{2} + 1)$ als $- 1 (x^{2} + 1)$ um.

$\frac{- 1 (x^{2} + 1)}{5 x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}}$

Schritt 1.17.9

Ziehe das Minuszeichen vor den Bruch.

$f' (x) = - \frac{x^{2} + 1}{5 x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}}$

Schritt 2

Bestimme die zweite Ableitung.

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Schritt 2.1

Da $- \frac{1}{5}$ konstant bezüglich $x$ ist, ist die Ableitung von $- \frac{x^{2} + 1}{5 x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}}$ nach $x$ gleich $- \frac{1}{5} \frac{d}{d x} [\frac{x^{2} + 1}{x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}}]$ .

$- \frac{1}{5} \frac{d}{d x} [\frac{x^{2} + 1}{x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}}]$

Schritt 2.2

$- \frac{1}{5} \cdot \frac{x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{2} + 1] - (x^{2} + 1) \frac{d}{d x} [x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}]}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.3

Differenziere.

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Schritt 2.3.1

Gemäß der Summenregel ist die Ableitung von $x^{2} + 1$ nach $x$ $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [1]$ .

$- \frac{1}{5} \cdot \frac{x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}} (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [1]) - (x^{2} + 1) \frac{d}{d x} [x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}]}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.3.2

Differenziere unter Anwendung der Potenzregel, die besagt, dass $\frac{d}{d x} [x^{n}]$ gleich $n x^{n - 1}$ ist mit $n = 2$ .

$- \frac{1}{5} \cdot \frac{x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}} (2 x + \frac{d}{d x} [1]) - (x^{2} + 1) \frac{d}{d x} [x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}]}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.3.3

Da $1$ konstant bezüglich $x$ ist, ist die Ableitung von $1$ bezüglich $x$ gleich $0$ .

$- \frac{1}{5} \cdot \frac{x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}} (2 x + 0) - (x^{2} + 1) \frac{d}{d x} [x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}]}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.3.4

Addiere $2 x$ und $0$ .

$- \frac{1}{5} \cdot \frac{x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}} (2 x) - (x^{2} + 1) \frac{d}{d x} [x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}]}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.4

Potenziere $x$ mit $1$ .

$- \frac{1}{5} \cdot \frac{x^{1} x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}} \cdot 2 - (x^{2} + 1) \frac{d}{d x} [x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}]}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.5

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$- \frac{1}{5} \cdot \frac{x^{1 + \frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}} \cdot 2 - (x^{2} + 1) \frac{d}{d x} [x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}]}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.6

Vereinfache den Ausdruck.

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Schritt 2.6.1

Schreibe $1$ als Bruch mit einem gemeinsamen Nenner.

$- \frac{1}{5} \cdot \frac{x^{\frac{5}{5} + \frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}} \cdot 2 - (x^{2} + 1) \frac{d}{d x} [x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}]}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.6.2

Vereinige die Zähler über dem gemeinsamen Nenner.

$- \frac{1}{5} \cdot \frac{x^{\frac{5 + 4}{5}} {(x^{2} - 1)}^{\frac{6}{5}} \cdot 2 - (x^{2} + 1) \frac{d}{d x} [x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}]}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.6.3

Addiere $5$ und $4$ .

$- \frac{1}{5} \cdot \frac{x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} \cdot 2 - (x^{2} + 1) \frac{d}{d x} [x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}]}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.6.4

Bringe $2$ auf die linke Seite von $x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}}$ .

$- \frac{1}{5} \cdot \frac{2 \cdot (x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}}) - (x^{2} + 1) \frac{d}{d x} [x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}]}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.7

Differenziere unter Anwendung der Produktregel, die besagt, dass $\frac{d}{d x} [f (x) g (x)]$ gleich $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ ist mit $f (x) = x^{\frac{4}{5}}$ und $g (x) = {(x^{2} - 1)}^{\frac{6}{5}}$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (x^{\frac{4}{5}} \frac{d}{d x} [{(x^{2} - 1)}^{\frac{6}{5}}] + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.8

Differenziere unter Anwendung der Kettenregel, die besagt, dass $\frac{d}{d x} [f (g (x))]$ ist $f' (g (x)) g' (x)$ , mit $f (x) = x^{\frac{6}{5}}$ und $g (x) = x^{2} - 1$ .

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Schritt 2.8.1

Um die Kettenregel anzuwenden, ersetze $u$ durch $x^{2} - 1$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (x^{\frac{4}{5}} (\frac{d}{d u} [u^{\frac{6}{5}}] \frac{d}{d x} [x^{2} - 1]) + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.8.2

Differenziere unter Anwendung der Potenzregel, die besagt, dass $\frac{d}{d u} [u^{n}]$ gleich $n u^{n - 1}$ ist mit $n = \frac{6}{5}$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (x^{\frac{4}{5}} (\frac{6}{5} u^{\frac{6}{5} - 1} \frac{d}{d x} [x^{2} - 1]) + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.8.3

Ersetze alle $u$ durch $x^{2} - 1$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (x^{\frac{4}{5}} (\frac{6}{5} {(x^{2} - 1)}^{\frac{6}{5} - 1} \frac{d}{d x} [x^{2} - 1]) + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.9

Um $- 1$ als Bruch mit einem gemeinsamen Nenner zu schreiben, multipliziere mit $\frac{5}{5}$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (x^{\frac{4}{5}} (\frac{6}{5} {(x^{2} - 1)}^{\frac{6}{5} - 1 \cdot \frac{5}{5}} \frac{d}{d x} [x^{2} - 1]) + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.10

Kombiniere $- 1$ und $\frac{5}{5}$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (x^{\frac{4}{5}} (\frac{6}{5} {(x^{2} - 1)}^{\frac{6}{5} + \frac{- 1 \cdot 5}{5}} \frac{d}{d x} [x^{2} - 1]) + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.11

Vereinige die Zähler über dem gemeinsamen Nenner.

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (x^{\frac{4}{5}} (\frac{6}{5} {(x^{2} - 1)}^{\frac{6 - 1 \cdot 5}{5}} \frac{d}{d x} [x^{2} - 1]) + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.12

Vereinfache den Zähler.

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Schritt 2.12.1

Mutltipliziere $- 1$ mit $5$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (x^{\frac{4}{5}} (\frac{6}{5} {(x^{2} - 1)}^{\frac{6 - 5}{5}} \frac{d}{d x} [x^{2} - 1]) + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.12.2

Subtrahiere $5$ von $6$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (x^{\frac{4}{5}} (\frac{6}{5} {(x^{2} - 1)}^{\frac{1}{5}} \frac{d}{d x} [x^{2} - 1]) + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.13

Kombiniere Brüche.

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Schritt 2.13.1

Kombiniere $\frac{6}{5}$ und ${(x^{2} - 1)}^{\frac{1}{5}}$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (x^{\frac{4}{5}} (\frac{6 {(x^{2} - 1)}^{\frac{1}{5}}}{5} \frac{d}{d x} [x^{2} - 1]) + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.13.2

Kombiniere $\frac{6 {(x^{2} - 1)}^{\frac{1}{5}}}{5}$ und $x^{\frac{4}{5}}$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{6 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{4}{5}}}{5} \frac{d}{d x} [x^{2} - 1] + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.14

Gemäß der Summenregel ist die Ableitung von $x^{2} - 1$ nach $x$ $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 1]$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{6 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{4}{5}}}{5} (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 1]) + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.15

Differenziere unter Anwendung der Potenzregel, die besagt, dass $\frac{d}{d x} [x^{n}]$ gleich $n x^{n - 1}$ ist mit $n = 2$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{6 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{4}{5}}}{5} (2 x + \frac{d}{d x} [- 1]) + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.16

Da $- 1$ konstant bezüglich $x$ ist, ist die Ableitung von $- 1$ bezüglich $x$ gleich $0$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{6 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{4}{5}}}{5} (2 x + 0) + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.17

Kombiniere Brüche.

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Schritt 2.17.1

Addiere $2 x$ und $0$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{6 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{4}{5}}}{5} (2 x) + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.17.2

Kombiniere $2$ und $\frac{6 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{4}{5}}}{5}$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{2 (6 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{4}{5}})}{5} x + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.17.3

Mutltipliziere $6$ mit $2$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 ({(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{4}{5}})}{5} x + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.17.4

Kombiniere $\frac{12 ({(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{4}{5}})}{5}$ und $x$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 ({(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{4}{5}}) x}{5} + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.18

Potenziere $x$ mit $1$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 ({(x^{2} - 1)}^{\frac{1}{5}} (x^{1} x^{\frac{4}{5}}))}{5} + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.19

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 ({(x^{2} - 1)}^{\frac{1}{5}} x^{1 + \frac{4}{5}})}{5} + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.20

Vereinfache den Ausdruck.

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Schritt 2.20.1

Schreibe $1$ als Bruch mit einem gemeinsamen Nenner.

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 ({(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{5}{5} + \frac{4}{5}})}{5} + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.20.2

Vereinige die Zähler über dem gemeinsamen Nenner.

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 ({(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{5 + 4}{5}})}{5} + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.20.3

Addiere $5$ und $4$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 ({(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{9}{5}})}{5} + {(x^{2} - 1)}^{\frac{6}{5}} \frac{d}{d x} [x^{\frac{4}{5}}])}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.21

Differenziere unter Anwendung der Potenzregel, die besagt, dass $\frac{d}{d x} [x^{n}]$ gleich $n x^{n - 1}$ ist mit $n = \frac{4}{5}$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{9}{5}}}{5} + {(x^{2} - 1)}^{\frac{6}{5}} (\frac{4}{5} x^{\frac{4}{5} - 1}))}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.22

Um $- 1$ als Bruch mit einem gemeinsamen Nenner zu schreiben, multipliziere mit $\frac{5}{5}$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{9}{5}}}{5} + {(x^{2} - 1)}^{\frac{6}{5}} (\frac{4}{5} x^{\frac{4}{5} - 1 \cdot \frac{5}{5}}))}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.23

Kombiniere $- 1$ und $\frac{5}{5}$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{9}{5}}}{5} + {(x^{2} - 1)}^{\frac{6}{5}} (\frac{4}{5} x^{\frac{4}{5} + \frac{- 1 \cdot 5}{5}}))}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.24

Vereinige die Zähler über dem gemeinsamen Nenner.

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{9}{5}}}{5} + {(x^{2} - 1)}^{\frac{6}{5}} (\frac{4}{5} x^{\frac{4 - 1 \cdot 5}{5}}))}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.25

Vereinfache den Zähler.

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Schritt 2.25.1

Mutltipliziere $- 1$ mit $5$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{9}{5}}}{5} + {(x^{2} - 1)}^{\frac{6}{5}} (\frac{4}{5} x^{\frac{4 - 5}{5}}))}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.25.2

Subtrahiere $5$ von $4$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{9}{5}}}{5} + {(x^{2} - 1)}^{\frac{6}{5}} (\frac{4}{5} x^{\frac{- 1}{5}}))}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.26

Ziehe das Minuszeichen vor den Bruch.

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{9}{5}}}{5} + {(x^{2} - 1)}^{\frac{6}{5}} (\frac{4}{5} x^{- \frac{1}{5}}))}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.27

Kombiniere $\frac{4}{5}$ und $x^{- \frac{1}{5}}$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{9}{5}}}{5} + {(x^{2} - 1)}^{\frac{6}{5}} \frac{4 x^{- \frac{1}{5}}}{5})}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.28

Kombiniere ${(x^{2} - 1)}^{\frac{6}{5}}$ und $\frac{4 x^{- \frac{1}{5}}}{5}$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{9}{5}}}{5} + \frac{{(x^{2} - 1)}^{\frac{6}{5}} (4 x^{- \frac{1}{5}})}{5})}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.29

Vereinfache den Ausdruck.

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Schritt 2.29.1

Bringe $4$ auf die linke Seite von ${(x^{2} - 1)}^{\frac{6}{5}}$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{9}{5}}}{5} + \frac{4 \cdot {(x^{2} - 1)}^{\frac{6}{5}} x^{- \frac{1}{5}}}{5})}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.29.2

Bringe $x^{- \frac{1}{5}}$ in den Nenner mit Hilfe der Regel des negativen Exponenten $b^{- n} = \frac{1}{b^{n}}$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{9}{5}}}{5} + \frac{4 {(x^{2} - 1)}^{\frac{6}{5}}}{5 x^{\frac{1}{5}}})}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.30

Um $\frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{9}{5}}}{5}$ als Bruch mit einem gemeinsamen Nenner zu schreiben, multipliziere mit $\frac{x^{\frac{1}{5}}}{x^{\frac{1}{5}}}$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{9}{5}}}{5} \cdot \frac{x^{\frac{1}{5}}}{x^{\frac{1}{5}}} + \frac{4 {(x^{2} - 1)}^{\frac{6}{5}}}{5 x^{\frac{1}{5}}})}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.31

Mutltipliziere $\frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{9}{5}}}{5}$ mit $\frac{x^{\frac{1}{5}}}{x^{\frac{1}{5}}}$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) (\frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{9}{5}} x^{\frac{1}{5}}}{5 x^{\frac{1}{5}}} + \frac{4 {(x^{2} - 1)}^{\frac{6}{5}}}{5 x^{\frac{1}{5}}})}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.32

Vereinige die Zähler über dem gemeinsamen Nenner.

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) \frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{9}{5}} x^{\frac{1}{5}} + 4 {(x^{2} - 1)}^{\frac{6}{5}}}{5 x^{\frac{1}{5}}}}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.33

Multipliziere $x^{\frac{9}{5}}$ mit $x^{\frac{1}{5}}$ durch Addieren der Exponenten.

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Schritt 2.33.1

Bewege $x^{\frac{1}{5}}$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) \frac{12 {(x^{2} - 1)}^{\frac{1}{5}} (x^{\frac{1}{5}} x^{\frac{9}{5}}) + 4 {(x^{2} - 1)}^{\frac{6}{5}}}{5 x^{\frac{1}{5}}}}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.33.2

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) \frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{1}{5} + \frac{9}{5}} + 4 {(x^{2} - 1)}^{\frac{6}{5}}}{5 x^{\frac{1}{5}}}}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.33.3

Vereinige die Zähler über dem gemeinsamen Nenner.

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) \frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{1 + 9}{5}} + 4 {(x^{2} - 1)}^{\frac{6}{5}}}{5 x^{\frac{1}{5}}}}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.33.4

Addiere $1$ und $9$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) \frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{\frac{10}{5}} + 4 {(x^{2} - 1)}^{\frac{6}{5}}}{5 x^{\frac{1}{5}}}}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.33.5

Dividiere $10$ durch $5$ .

$- \frac{1}{5} \cdot \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) \frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{2} + 4 {(x^{2} - 1)}^{\frac{6}{5}}}{5 x^{\frac{1}{5}}}}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.34

Mutltipliziere $\frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) \frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{2} + 4 {(x^{2} - 1)}^{\frac{6}{5}}}{5 x^{\frac{1}{5}}}}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$ mit $\frac{1}{5}$ .

$- \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) \frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{2} + 4 {(x^{2} - 1)}^{\frac{6}{5}}}{5 x^{\frac{1}{5}}}}{{(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2} \cdot 5}$

Schritt 2.35

Bringe $5$ auf die linke Seite von ${(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}$ .

$- \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) \frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{2} + 4 {(x^{2} - 1)}^{\frac{6}{5}}}{5 x^{\frac{1}{5}}}}{5 \cdot {(x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}})}^{2}}$

Schritt 2.36

Vereinfache.

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Schritt 2.36.1

Wende die Produktregel auf $x^{\frac{4}{5}} {(x^{2} - 1)}^{\frac{6}{5}}$ an.

$- \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} - (x^{2} + 1) \frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{2} + 4 {(x^{2} - 1)}^{\frac{6}{5}}}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.2

Wende das Distributivgesetz an.

$- \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} + (- x^{2} - 1 \cdot 1) \frac{12 {(x^{2} - 1)}^{\frac{1}{5}} x^{2} + 4 {(x^{2} - 1)}^{\frac{6}{5}}}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3

Vereinfache den Zähler.

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Schritt 2.36.3.1

Vereinfache den Zähler.

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Schritt 2.36.3.1.1

Faktorisiere $4 {(x^{2} - 1)}^{\frac{1}{5}}$ aus $12 {(x^{2} - 1)}^{\frac{1}{5}} x^{2} + 4 {(x^{2} - 1)}^{\frac{6}{5}}$ heraus.

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Schritt 2.36.3.1.1.1

Bewege ${(x^{2} - 1)}^{\frac{1}{5}}$ .

$- \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} + (- x^{2} - 1 \cdot 1) \frac{12 x^{2} {(x^{2} - 1)}^{\frac{1}{5}} + 4 {(x^{2} - 1)}^{\frac{6}{5}}}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.1.1.2

Faktorisiere $4 {(x^{2} - 1)}^{\frac{1}{5}}$ aus $12 x^{2} {(x^{2} - 1)}^{\frac{1}{5}}$ heraus.

$- \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} + (- x^{2} - 1 \cdot 1) \frac{4 {(x^{2} - 1)}^{\frac{1}{5}} (3 x^{2}) + 4 {(x^{2} - 1)}^{\frac{6}{5}}}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.1.1.3

Faktorisiere $4 {(x^{2} - 1)}^{\frac{1}{5}}$ aus $4 {(x^{2} - 1)}^{\frac{6}{5}}$ heraus.

$- \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} + (- x^{2} - 1 \cdot 1) \frac{4 {(x^{2} - 1)}^{\frac{1}{5}} (3 x^{2}) + 4 {(x^{2} - 1)}^{\frac{1}{5}} ({(x^{2} - 1)}^{\frac{5}{5}})}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.1.1.4

Faktorisiere $4 {(x^{2} - 1)}^{\frac{1}{5}}$ aus $4 {(x^{2} - 1)}^{\frac{1}{5}} (3 x^{2}) + 4 {(x^{2} - 1)}^{\frac{1}{5}} ({(x^{2} - 1)}^{\frac{5}{5}})$ heraus.

$- \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} + (- x^{2} - 1 \cdot 1) \frac{4 {(x^{2} - 1)}^{\frac{1}{5}} (3 x^{2} + {(x^{2} - 1)}^{\frac{5}{5}})}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.1.2

Dividiere $5$ durch $5$ .

$- \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} + (- x^{2} - 1 \cdot 1) \frac{4 {(x^{2} - 1)}^{\frac{1}{5}} (3 x^{2} + {(x^{2} - 1)}^{1})}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.1.3

Vereinfache.

$- \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} + (- x^{2} - 1 \cdot 1) \frac{4 {(x^{2} - 1)}^{\frac{1}{5}} (3 x^{2} + x^{2} - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.1.4

Addiere $3 x^{2}$ und $x^{2}$ .

$- \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} + (- x^{2} - 1 \cdot 1) \frac{4 {(x^{2} - 1)}^{\frac{1}{5}} (4 x^{2} - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.1.5

Schreibe $4 x^{2} - 1$ in eine faktorisierte Form um.

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Schritt 2.36.3.1.5.1

Schreibe $4 x^{2}$ als ${(2 x)}^{2}$ um.

$- \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} + (- x^{2} - 1 \cdot 1) \frac{4 {(x^{2} - 1)}^{\frac{1}{5}} ({(2 x)}^{2} - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.1.5.2

Schreibe $1$ als $1^{2}$ um.

$- \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} + (- x^{2} - 1 \cdot 1) \frac{4 {(x^{2} - 1)}^{\frac{1}{5}} ({(2 x)}^{2} - 1^{2})}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.1.5.3

Da beide Terme perfekte Quadrate sind, faktorisiere durch Anwendung der dritten binomischen Formel, $a^{2} - b^{2} = (a + b) (a - b)$ , mit $a = 2 x$ und $b = 1$ .

$- \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} + (- x^{2} - 1 \cdot 1) \frac{4 {(x^{2} - 1)}^{\frac{1}{5}} ((2 x + 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

$- \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} + (- x^{2} - 1 \cdot 1) \frac{4 {(x^{2} - 1)}^{\frac{1}{5}} (2 x + 1) (2 x - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.2

Mutltipliziere $- 1$ mit $1$ .

$- \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} + (- x^{2} - 1) \frac{4 {(x^{2} - 1)}^{\frac{1}{5}} (2 x + 1) (2 x - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.3

Mutltipliziere $- x^{2} - 1$ mit $\frac{4 {(x^{2} - 1)}^{\frac{1}{5}} (2 x + 1) (2 x - 1)}{5 x^{\frac{1}{5}}}$ .

$- \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} + \frac{(- x^{2} - 1) (4 {(x^{2} - 1)}^{\frac{1}{5}} (2 x + 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.4

Bringe $4$ auf die linke Seite von $- x^{2} - 1$ .

$- \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} + \frac{4 \cdot (- x^{2} - 1) {(x^{2} - 1)}^{\frac{1}{5}} (2 x + 1) (2 x - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.5

Um $2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}}$ als Bruch mit einem gemeinsamen Nenner zu schreiben, multipliziere mit $\frac{5 x^{\frac{1}{5}}}{5 x^{\frac{1}{5}}}$ .

$- \frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} \cdot \frac{5 x^{\frac{1}{5}}}{5 x^{\frac{1}{5}}} + \frac{4 (- x^{2} - 1) {(x^{2} - 1)}^{\frac{1}{5}} (2 x + 1) (2 x - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.6

Kombiniere $2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}}$ und $\frac{5 x^{\frac{1}{5}}}{5 x^{\frac{1}{5}}}$ .

$- \frac{\frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} (5 x^{\frac{1}{5}})}{5 x^{\frac{1}{5}}} + \frac{4 (- x^{2} - 1) {(x^{2} - 1)}^{\frac{1}{5}} (2 x + 1) (2 x - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.7

Vereinige die Zähler über dem gemeinsamen Nenner.

$- \frac{\frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} (5 x^{\frac{1}{5}}) + 4 (- x^{2} - 1) {(x^{2} - 1)}^{\frac{1}{5}} (2 x + 1) (2 x - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.8

Schreibe $\frac{2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} (5 x^{\frac{1}{5}}) + 4 (- x^{2} - 1) {(x^{2} - 1)}^{\frac{1}{5}} (2 x + 1) (2 x - 1)}{5 x^{\frac{1}{5}}}$ in eine faktorisierte Form um.

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Schritt 2.36.3.8.1

Faktorisiere $2 {(x^{2} - 1)}^{\frac{1}{5}}$ aus $2 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{6}{5}} (5 x^{\frac{1}{5}}) + 4 (- x^{2} - 1) {(x^{2} - 1)}^{\frac{1}{5}} (2 x + 1) (2 x - 1)$ heraus.

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Schritt 2.36.3.8.1.1

Stelle den Ausdruck um.

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Schritt 2.36.3.8.1.1.1

Bewege ${(x^{2} - 1)}^{\frac{6}{5}}$ .

$- \frac{\frac{2 x^{\frac{9}{5}} \cdot 5 x^{\frac{1}{5}} {(x^{2} - 1)}^{\frac{6}{5}} + 4 (- x^{2} - 1) {(x^{2} - 1)}^{\frac{1}{5}} (2 x + 1) (2 x - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.8.1.1.2

Bewege $x^{\frac{9}{5}}$ .

$- \frac{\frac{2 \cdot 5 x^{\frac{9}{5}} x^{\frac{1}{5}} {(x^{2} - 1)}^{\frac{6}{5}} + 4 (- x^{2} - 1) {(x^{2} - 1)}^{\frac{1}{5}} (2 x + 1) (2 x - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.8.1.2

Faktorisiere $2 {(x^{2} - 1)}^{\frac{1}{5}}$ aus $2 \cdot 5 x^{\frac{9}{5}} x^{\frac{1}{5}} {(x^{2} - 1)}^{\frac{6}{5}}$ heraus.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{\frac{9}{5}} x^{\frac{1}{5}} {(x^{2} - 1)}^{\frac{5}{5}}) + 4 (- x^{2} - 1) {(x^{2} - 1)}^{\frac{1}{5}} (2 x + 1) (2 x - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.8.1.3

Faktorisiere $2 {(x^{2} - 1)}^{\frac{1}{5}}$ aus $4 (- x^{2} - 1) {(x^{2} - 1)}^{\frac{1}{5}} (2 x + 1) (2 x - 1)$ heraus.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{\frac{9}{5}} x^{\frac{1}{5}} {(x^{2} - 1)}^{\frac{5}{5}}) + 2 {(x^{2} - 1)}^{\frac{1}{5}} ((2 (- x^{2} - 1) (2 x + 1)) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.8.1.4

Faktorisiere $2 {(x^{2} - 1)}^{\frac{1}{5}}$ aus $2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{\frac{9}{5}} x^{\frac{1}{5}} {(x^{2} - 1)}^{\frac{5}{5}}) + 2 {(x^{2} - 1)}^{\frac{1}{5}} ((2 (- x^{2} - 1) (2 x + 1)) (2 x - 1))$ heraus.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{\frac{9}{5}} x^{\frac{1}{5}} {(x^{2} - 1)}^{\frac{5}{5}} + (2 (- x^{2} - 1) (2 x + 1)) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.8.2

Multipliziere $x^{\frac{9}{5}}$ mit $x^{\frac{1}{5}}$ durch Addieren der Exponenten.

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Schritt 2.36.3.8.2.1

Bewege $x^{\frac{1}{5}}$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 (x^{\frac{1}{5}} x^{\frac{9}{5}}) {(x^{2} - 1)}^{\frac{5}{5}} + (2 (- x^{2} - 1) (2 x + 1)) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.8.2.2

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{\frac{1}{5} + \frac{9}{5}} {(x^{2} - 1)}^{\frac{5}{5}} + (2 (- x^{2} - 1) (2 x + 1)) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.8.2.3

Vereinige die Zähler über dem gemeinsamen Nenner.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{\frac{1 + 9}{5}} {(x^{2} - 1)}^{\frac{5}{5}} + (2 (- x^{2} - 1) (2 x + 1)) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.8.2.4

Addiere $1$ und $9$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{\frac{10}{5}} {(x^{2} - 1)}^{\frac{5}{5}} + (2 (- x^{2} - 1) (2 x + 1)) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.8.2.5

Dividiere $10$ durch $5$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{2} {(x^{2} - 1)}^{\frac{5}{5}} + (2 (- x^{2} - 1) (2 x + 1)) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.9

Kürze den gemeinsamen Faktor von $5$ .

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Schritt 2.36.3.9.1

Kürze den gemeinsamen Faktor.

Schritt 2.36.3.9.2

Forme den Ausdruck um.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{2} {(x^{2} - 1)}^{1} + (2 (- x^{2} - 1) (2 x + 1)) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10

Vereinfache den Zähler.

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Schritt 2.36.3.10.1

Vereinfache.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{2} (x^{2} - 1) + 2 (- x^{2} - 1) (2 x + 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.2

Wende das Distributivgesetz an.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{2} x^{2} + 5 x^{2} \cdot - 1 + 2 (- x^{2} - 1) (2 x + 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.3

Multipliziere $x^{2}$ mit $x^{2}$ durch Addieren der Exponenten.

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Schritt 2.36.3.10.3.1

Bewege $x^{2}$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 (x^{2} x^{2}) + 5 x^{2} \cdot - 1 + 2 (- x^{2} - 1) (2 x + 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.3.2

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{2 + 2} + 5 x^{2} \cdot - 1 + 2 (- x^{2} - 1) (2 x + 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.3.3

Addiere $2$ und $2$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} + 5 x^{2} \cdot - 1 + 2 (- x^{2} - 1) (2 x + 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.4

Mutltipliziere $- 1$ mit $5$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} + 2 (- x^{2} - 1) (2 x + 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.5

Wende das Distributivgesetz an.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} + (2 (- x^{2}) + 2 \cdot - 1) (2 x + 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.6

Mutltipliziere $- 1$ mit $2$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} + (- 2 x^{2} + 2 \cdot - 1) (2 x + 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.7

Mutltipliziere $2$ mit $- 1$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} + (- 2 x^{2} - 2) (2 x + 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.8

Multipliziere $(- 2 x^{2} - 2) (2 x + 1)$ aus unter Verwendung der FOIL-Methode.

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Schritt 2.36.3.10.8.1

Wende das Distributivgesetz an.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} + (- 2 x^{2} (2 x + 1) - 2 (2 x + 1)) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.8.2

Wende das Distributivgesetz an.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} + (- 2 x^{2} (2 x) - 2 x^{2} \cdot 1 - 2 (2 x + 1)) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.8.3

Wende das Distributivgesetz an.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} + (- 2 x^{2} (2 x) - 2 x^{2} \cdot 1 - 2 (2 x) - 2 \cdot 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.9

Vereinfache jeden Term.

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Schritt 2.36.3.10.9.1

Schreibe neu unter Anwendung des Kommutativgesetzes der Multiplikation.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} + (- 2 \cdot 2 x^{2} x - 2 x^{2} \cdot 1 - 2 (2 x) - 2 \cdot 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.9.2

Multipliziere $x^{2}$ mit $x$ durch Addieren der Exponenten.

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Schritt 2.36.3.10.9.2.1

Bewege $x$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} + (- 2 \cdot 2 (x \cdot x^{2}) - 2 x^{2} \cdot 1 - 2 (2 x) - 2 \cdot 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.9.2.2

Mutltipliziere $x$ mit $x^{2}$ .

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Schritt 2.36.3.10.9.2.2.1

Potenziere $x$ mit $1$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} + (- 2 \cdot 2 (x^{1} x^{2}) - 2 x^{2} \cdot 1 - 2 (2 x) - 2 \cdot 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.9.2.2.2

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} + (- 2 \cdot 2 x^{1 + 2} - 2 x^{2} \cdot 1 - 2 (2 x) - 2 \cdot 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.9.2.3

Addiere $1$ und $2$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} + (- 2 \cdot 2 x^{3} - 2 x^{2} \cdot 1 - 2 (2 x) - 2 \cdot 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.9.3

Mutltipliziere $- 2$ mit $2$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} + (- 4 x^{3} - 2 x^{2} \cdot 1 - 2 (2 x) - 2 \cdot 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.9.4

Mutltipliziere $- 2$ mit $1$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} + (- 4 x^{3} - 2 x^{2} - 2 (2 x) - 2 \cdot 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.9.5

Mutltipliziere $2$ mit $- 2$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} + (- 4 x^{3} - 2 x^{2} - 4 x - 2 \cdot 1) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.9.6

Mutltipliziere $- 2$ mit $1$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} + (- 4 x^{3} - 2 x^{2} - 4 x - 2) (2 x - 1))}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.10

Multipliziere $(- 4 x^{3} - 2 x^{2} - 4 x - 2) (2 x - 1)$ aus durch Multiplizieren jedes Terms des ersten Ausdrucks mit jedem Term des zweiten Ausdrucks.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 4 x^{3} (2 x) - 4 x^{3} \cdot - 1 - 2 x^{2} (2 x) - 2 x^{2} \cdot - 1 - 4 x (2 x) - 4 x \cdot - 1 - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11

Vereinfache jeden Term.

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Schritt 2.36.3.10.11.1

Schreibe neu unter Anwendung des Kommutativgesetzes der Multiplikation.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 4 \cdot 2 x^{3} x - 4 x^{3} \cdot - 1 - 2 x^{2} (2 x) - 2 x^{2} \cdot - 1 - 4 x (2 x) - 4 x \cdot - 1 - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.2

Multipliziere $x^{3}$ mit $x$ durch Addieren der Exponenten.

Tippen, um mehr Schritte zu sehen ...

Schritt 2.36.3.10.11.2.1

Bewege $x$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 4 \cdot 2 (x \cdot x^{3}) - 4 x^{3} \cdot - 1 - 2 x^{2} (2 x) - 2 x^{2} \cdot - 1 - 4 x (2 x) - 4 x \cdot - 1 - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.2.2

Mutltipliziere $x$ mit $x^{3}$ .

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Schritt 2.36.3.10.11.2.2.1

Potenziere $x$ mit $1$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 4 \cdot 2 (x^{1} x^{3}) - 4 x^{3} \cdot - 1 - 2 x^{2} (2 x) - 2 x^{2} \cdot - 1 - 4 x (2 x) - 4 x \cdot - 1 - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.2.2.2

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 4 \cdot 2 x^{1 + 3} - 4 x^{3} \cdot - 1 - 2 x^{2} (2 x) - 2 x^{2} \cdot - 1 - 4 x (2 x) - 4 x \cdot - 1 - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.2.3

Addiere $1$ und $3$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 4 \cdot 2 x^{4} - 4 x^{3} \cdot - 1 - 2 x^{2} (2 x) - 2 x^{2} \cdot - 1 - 4 x (2 x) - 4 x \cdot - 1 - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.3

Mutltipliziere $- 4$ mit $2$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} - 4 x^{3} \cdot - 1 - 2 x^{2} (2 x) - 2 x^{2} \cdot - 1 - 4 x (2 x) - 4 x \cdot - 1 - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.4

Mutltipliziere $- 1$ mit $- 4$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} + 4 x^{3} - 2 x^{2} (2 x) - 2 x^{2} \cdot - 1 - 4 x (2 x) - 4 x \cdot - 1 - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.5

Schreibe neu unter Anwendung des Kommutativgesetzes der Multiplikation.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} + 4 x^{3} - 2 \cdot 2 x^{2} x - 2 x^{2} \cdot - 1 - 4 x (2 x) - 4 x \cdot - 1 - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.6

Multipliziere $x^{2}$ mit $x$ durch Addieren der Exponenten.

Tippen, um mehr Schritte zu sehen ...

Schritt 2.36.3.10.11.6.1

Bewege $x$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} + 4 x^{3} - 2 \cdot 2 (x \cdot x^{2}) - 2 x^{2} \cdot - 1 - 4 x (2 x) - 4 x \cdot - 1 - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.6.2

Mutltipliziere $x$ mit $x^{2}$ .

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Schritt 2.36.3.10.11.6.2.1

Potenziere $x$ mit $1$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} + 4 x^{3} - 2 \cdot 2 (x^{1} x^{2}) - 2 x^{2} \cdot - 1 - 4 x (2 x) - 4 x \cdot - 1 - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.6.2.2

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} + 4 x^{3} - 2 \cdot 2 x^{1 + 2} - 2 x^{2} \cdot - 1 - 4 x (2 x) - 4 x \cdot - 1 - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.6.3

Addiere $1$ und $2$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} + 4 x^{3} - 2 \cdot 2 x^{3} - 2 x^{2} \cdot - 1 - 4 x (2 x) - 4 x \cdot - 1 - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.7

Mutltipliziere $- 2$ mit $2$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} + 4 x^{3} - 4 x^{3} - 2 x^{2} \cdot - 1 - 4 x (2 x) - 4 x \cdot - 1 - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.8

Mutltipliziere $- 1$ mit $- 2$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} + 4 x^{3} - 4 x^{3} + 2 x^{2} - 4 x (2 x) - 4 x \cdot - 1 - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.9

Schreibe neu unter Anwendung des Kommutativgesetzes der Multiplikation.

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} + 4 x^{3} - 4 x^{3} + 2 x^{2} - 4 \cdot 2 x \cdot x - 4 x \cdot - 1 - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.10

Multipliziere $x$ mit $x$ durch Addieren der Exponenten.

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Schritt 2.36.3.10.11.10.1

Bewege $x$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} + 4 x^{3} - 4 x^{3} + 2 x^{2} - 4 \cdot 2 (x \cdot x) - 4 x \cdot - 1 - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.10.2

Mutltipliziere $x$ mit $x$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} + 4 x^{3} - 4 x^{3} + 2 x^{2} - 4 \cdot 2 x^{2} - 4 x \cdot - 1 - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.11

Mutltipliziere $- 4$ mit $2$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} + 4 x^{3} - 4 x^{3} + 2 x^{2} - 8 x^{2} - 4 x \cdot - 1 - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.12

Mutltipliziere $- 1$ mit $- 4$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} + 4 x^{3} - 4 x^{3} + 2 x^{2} - 8 x^{2} + 4 x - 2 (2 x) - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.13

Mutltipliziere $2$ mit $- 2$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} + 4 x^{3} - 4 x^{3} + 2 x^{2} - 8 x^{2} + 4 x - 4 x - 2 \cdot - 1)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.11.14

Mutltipliziere $- 2$ mit $- 1$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} + 4 x^{3} - 4 x^{3} + 2 x^{2} - 8 x^{2} + 4 x - 4 x + 2)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.12

Vereine die Terme mit entgegengesetztem Vorzeichen in $- 8 x^{4} + 4 x^{3} - 4 x^{3} + 2 x^{2} - 8 x^{2} + 4 x - 4 x + 2$ .

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Schritt 2.36.3.10.12.1

Subtrahiere $4 x^{3}$ von $4 x^{3}$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} + 0 + 2 x^{2} - 8 x^{2} + 4 x - 4 x + 2)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.12.2

Addiere $- 8 x^{4}$ und $0$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} + 2 x^{2} - 8 x^{2} + 4 x - 4 x + 2)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.12.3

Subtrahiere $4 x$ von $4 x$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} + 2 x^{2} - 8 x^{2} + 0 + 2)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.12.4

Addiere $- 8 x^{4} + 2 x^{2} - 8 x^{2}$ und $0$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} + 2 x^{2} - 8 x^{2} + 2)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.13

Subtrahiere $8 x^{2}$ von $2 x^{2}$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (5 x^{4} - 5 x^{2} - 8 x^{4} - 6 x^{2} + 2)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.14

Subtrahiere $8 x^{4}$ von $5 x^{4}$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (- 3 x^{4} - 5 x^{2} - 6 x^{2} + 2)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.3.10.15

Subtrahiere $6 x^{2}$ von $- 5 x^{2}$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (- 3 x^{4} - 11 x^{2} + 2)}{5 x^{\frac{1}{5}}}}{5 ({(x^{\frac{4}{5}})}^{2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.4

Vereine die Terme

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Schritt 2.36.4.1

Multipliziere die Exponenten in ${(x^{\frac{4}{5}})}^{2}$ .

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Schritt 2.36.4.1.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (- 3 x^{4} - 11 x^{2} + 2)}{5 x^{\frac{1}{5}}}}{5 (x^{\frac{4}{5} \cdot 2} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.4.1.2

Multipliziere $\frac{4}{5} \cdot 2$ .

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Schritt 2.36.4.1.2.1

Kombiniere $\frac{4}{5}$ und $2$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (- 3 x^{4} - 11 x^{2} + 2)}{5 x^{\frac{1}{5}}}}{5 (x^{\frac{4 \cdot 2}{5}} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.4.1.2.2

Mutltipliziere $4$ mit $2$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (- 3 x^{4} - 11 x^{2} + 2)}{5 x^{\frac{1}{5}}}}{5 (x^{\frac{8}{5}} {({(x^{2} - 1)}^{\frac{6}{5}})}^{2})}$

Schritt 2.36.4.2

Multipliziere die Exponenten in ${({(x^{2} - 1)}^{\frac{6}{5}})}^{2}$ .

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Schritt 2.36.4.2.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (- 3 x^{4} - 11 x^{2} + 2)}{5 x^{\frac{1}{5}}}}{5 (x^{\frac{8}{5}} {(x^{2} - 1)}^{\frac{6}{5} \cdot 2})}$

Schritt 2.36.4.2.2

Multipliziere $\frac{6}{5} \cdot 2$ .

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Schritt 2.36.4.2.2.1

Kombiniere $\frac{6}{5}$ und $2$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (- 3 x^{4} - 11 x^{2} + 2)}{5 x^{\frac{1}{5}}}}{5 (x^{\frac{8}{5}} {(x^{2} - 1)}^{\frac{6 \cdot 2}{5}})}$

Schritt 2.36.4.2.2.2

Mutltipliziere $6$ mit $2$ .

$- \frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (- 3 x^{4} - 11 x^{2} + 2)}{5 x^{\frac{1}{5}}}}{5 (x^{\frac{8}{5}} {(x^{2} - 1)}^{\frac{12}{5}})}$

Schritt 2.36.4.3

Schreibe $\frac{\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (- 3 x^{4} - 11 x^{2} + 2)}{5 x^{\frac{1}{5}}}}{5 x^{\frac{8}{5}} {(x^{2} - 1)}^{\frac{12}{5}}}$ als ein Produkt um.

$- (\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (- 3 x^{4} - 11 x^{2} + 2)}{5 x^{\frac{1}{5}}} \cdot \frac{1}{5 x^{\frac{8}{5}} {(x^{2} - 1)}^{\frac{12}{5}}})$

Schritt 2.36.4.4

Mutltipliziere $\frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (- 3 x^{4} - 11 x^{2} + 2)}{5 x^{\frac{1}{5}}}$ mit $\frac{1}{5 x^{\frac{8}{5}} {(x^{2} - 1)}^{\frac{12}{5}}}$ .

$- \frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (- 3 x^{4} - 11 x^{2} + 2)}{5 x^{\frac{1}{5}} (5 x^{\frac{8}{5}} {(x^{2} - 1)}^{\frac{12}{5}})}$

Schritt 2.36.4.5

Mutltipliziere $5$ mit $5$ .

$- \frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (- 3 x^{4} - 11 x^{2} + 2)}{25 x^{\frac{1}{5}} (x^{\frac{8}{5}} {(x^{2} - 1)}^{\frac{12}{5}})}$

Schritt 2.36.4.6

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$- \frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (- 3 x^{4} - 11 x^{2} + 2)}{25 x^{\frac{8}{5} + \frac{1}{5}} {(x^{2} - 1)}^{\frac{12}{5}}}$

Schritt 2.36.4.7

Vereinige die Zähler über dem gemeinsamen Nenner.

$- \frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (- 3 x^{4} - 11 x^{2} + 2)}{25 x^{\frac{8 + 1}{5}} {(x^{2} - 1)}^{\frac{12}{5}}}$

Schritt 2.36.4.8

Addiere $8$ und $1$ .

$- \frac{2 {(x^{2} - 1)}^{\frac{1}{5}} (- 3 x^{4} - 11 x^{2} + 2)}{25 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{12}{5}}}$

Schritt 2.36.4.9

Bringe ${(x^{2} - 1)}^{\frac{1}{5}}$ in den Nenner mit Hilfe der Regel des negativen Exponenten $b^{n} = \frac{1}{b^{- n}}$ .

$- \frac{2 (- 3 x^{4} - 11 x^{2} + 2)}{25 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{12}{5}} {(x^{2} - 1)}^{- \frac{1}{5}}}$

Schritt 2.36.4.10

Multipliziere ${(x^{2} - 1)}^{\frac{12}{5}}$ mit ${(x^{2} - 1)}^{- \frac{1}{5}}$ durch Addieren der Exponenten.

Tippen, um mehr Schritte zu sehen ...

Schritt 2.36.4.10.1

Bewege ${(x^{2} - 1)}^{- \frac{1}{5}}$ .

$- \frac{2 (- 3 x^{4} - 11 x^{2} + 2)}{25 x^{\frac{9}{5}} ({(x^{2} - 1)}^{- \frac{1}{5}} {(x^{2} - 1)}^{\frac{12}{5}})}$

Schritt 2.36.4.10.2

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$- \frac{2 (- 3 x^{4} - 11 x^{2} + 2)}{25 x^{\frac{9}{5}} {(x^{2} - 1)}^{- \frac{1}{5} + \frac{12}{5}}}$

Schritt 2.36.4.10.3

Vereinige die Zähler über dem gemeinsamen Nenner.

$- \frac{2 (- 3 x^{4} - 11 x^{2} + 2)}{25 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{- 1 + 12}{5}}}$

Schritt 2.36.4.10.4

Addiere $- 1$ und $12$ .

$- \frac{2 (- 3 x^{4} - 11 x^{2} + 2)}{25 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{11}{5}}}$

Schritt 2.36.5

Faktorisiere $- 1$ aus $- 3 x^{4}$ heraus.

$- \frac{2 (- (3 x^{4}) - 11 x^{2} + 2)}{25 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{11}{5}}}$

Schritt 2.36.6

Faktorisiere $- 1$ aus $- 11 x^{2}$ heraus.

$- \frac{2 (- (3 x^{4}) - (11 x^{2}) + 2)}{25 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{11}{5}}}$

Schritt 2.36.7

Faktorisiere $- 1$ aus $- (3 x^{4}) - (11 x^{2})$ heraus.

$- \frac{2 (- (3 x^{4} + 11 x^{2}) + 2)}{25 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{11}{5}}}$

Schritt 2.36.8

Schreibe $2$ als $- 1 (- 2)$ um.

$- \frac{2 (- (3 x^{4} + 11 x^{2}) - 1 (- 2))}{25 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{11}{5}}}$

Schritt 2.36.9

Faktorisiere $- 1$ aus $- (3 x^{4} + 11 x^{2}) - 1 (- 2)$ heraus.

$- \frac{2 (- (3 x^{4} + 11 x^{2} - 2))}{25 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{11}{5}}}$

Schritt 2.36.10

Schreibe $- (3 x^{4} + 11 x^{2} - 2)$ als $- 1 (3 x^{4} + 11 x^{2} - 2)$ um.

$- \frac{2 (- 1 (3 x^{4} + 11 x^{2} - 2))}{25 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{11}{5}}}$

Schritt 2.36.11

Ziehe das Minuszeichen vor den Bruch.

$- - \frac{2 (3 x^{4} + 11 x^{2} - 2)}{25 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{11}{5}}}$

Schritt 2.36.12

Mutltipliziere $- 1$ mit $- 1$ .

$1 \frac{2 (3 x^{4} + 11 x^{2} - 2)}{25 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{11}{5}}}$

Schritt 2.36.13

Mutltipliziere $\frac{2 (3 x^{4} + 11 x^{2} - 2)}{25 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{11}{5}}}$ mit $1$ .

$f'' (x) = \frac{2 (3 x^{4} + 11 x^{2} - 2)}{25 x^{\frac{9}{5}} {(x^{2} - 1)}^{\frac{11}{5}}}$