Algebra Beispiele

$2 x {(5 x - 1)}^{\frac{4}{5}} + 7 {(5 x - 1)}^{\frac{9}{5}}$

Schritt 1

Faktorisiere ${(5 x - 1)}^{\frac{4}{5}}$ aus $2 x {(5 x - 1)}^{\frac{4}{5}} + 7 {(5 x - 1)}^{\frac{9}{5}}$ heraus.

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Schritt 1.1

Faktorisiere ${(5 x - 1)}^{\frac{4}{5}}$ aus $2 x {(5 x - 1)}^{\frac{4}{5}}$ heraus.

${(5 x - 1)}^{\frac{4}{5}} (2 x) + 7 {(5 x - 1)}^{\frac{9}{5}}$

Schritt 1.2

Faktorisiere ${(5 x - 1)}^{\frac{4}{5}}$ aus $7 {(5 x - 1)}^{\frac{9}{5}}$ heraus.

${(5 x - 1)}^{\frac{4}{5}} (2 x) + {(5 x - 1)}^{\frac{4}{5}} (7 {(5 x - 1)}^{\frac{5}{5}})$

Schritt 1.3

Faktorisiere ${(5 x - 1)}^{\frac{4}{5}}$ aus ${(5 x - 1)}^{\frac{4}{5}} (2 x) + {(5 x - 1)}^{\frac{4}{5}} (7 {(5 x - 1)}^{\frac{5}{5}})$ heraus.

${(5 x - 1)}^{\frac{4}{5}} (2 x + 7 {(5 x - 1)}^{\frac{5}{5}})$

Schritt 2

Dividiere $5$ durch $5$ .

${(5 x - 1)}^{\frac{4}{5}} (2 x + 7 {(5 x - 1)}^{1})$

Schritt 3

Vereinfache.

${(5 x - 1)}^{\frac{4}{5}} (2 x + 7 (5 x - 1))$

Schritt 4

Wende das Distributivgesetz an.

${(5 x - 1)}^{\frac{4}{5}} (2 x + 7 (5 x) + 7 \cdot - 1)$

Schritt 5

Mutltipliziere $5$ mit $7$ .

${(5 x - 1)}^{\frac{4}{5}} (2 x + 35 x + 7 \cdot - 1)$

Schritt 6

Mutltipliziere $7$ mit $- 1$ .

${(5 x - 1)}^{\frac{4}{5}} (2 x + 35 x - 7)$

Schritt 7

Addiere $2 x$ und $35 x$ .

${(5 x - 1)}^{\frac{4}{5}} (37 x - 7)$